Answer:
M2 = 0.06404
P2 = 2.273
T2 = 5806.45°R
Explanation:
Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.
Therefore from Steam Table, Po1 = (1.028)*(10) = 10.28 atm,
To1 = (1.008)*(1000) = 1008 ºR
R = 1716 ft-lb/slug-ºR cp= 6006 ft-lb/slug-ºR fuel-air ratio (by mass)
F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga
For the air q = cp(To2– To1)
(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2
Table A.3 of steam table gives P/P* = 2.273,
T/T* = 0.2066,
To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =
F/A = 0.06404 slugf/slugaor less to prevent choked flow at the exit
(i) The density of the solid is 950 kg/m³
(ii) the density of another liquid in which the same solid would float is 200 kg/m³
The given parameters;
mass of the solid in air, Ma = 237.5 g
mass of the solid in liquid, Ms = 12.5 g
density of the liquid,
(i) The density of the solid is calculated as follows;
Weight in air - Weight in liquid = upthrust
(ii) the density of another liquid in which the same solid would float with one-fifth of its volume exposed above the liquid surface.
This is a low density liquid, because one-fifth of the solid is above the liquid surface while four-fifth is below the liquid surface.
the specific gravity of the liquid = ¹/₅ = 0.2
density of water ,
Thus, the density of another liquid in which the same solid would float is 200 kg/m³
Learn more here: brainly.com/question/14400760
Paint is immiscible because the layer that forms on top of settled paint is a substance which cannot dissolve with the rest of the paint. Stirring the paint is only temporarily in effort to form an even and thoroughly mixed solution by physically mixing the separate molecules of the solution. However, for it to be miscible, it the solution has to be evenly distributed (chemically) on a molecular level as to not separate when left for a lengthy period of time.
Answer:
No there won't be.
Explanation:
An insulator does not conduct electricity readily. An insulator that is charged at one end will have the charges remain at that end, since it does not allow the free flow of charges through it. If you touch the other end of the insulator that is void of electric charges, there would be no charge transfer between you and the insulator, and hence no electric shock.