Question

A solid weighs 237.5 g in air and 12.5 g in a liquid in which it is wholly submerged. The density of the liquid is 900 kg/m³.

Answer 1

(i) The density of the solid is 950 kg/m³

(ii) the density of another liquid in which the same solid would float is 200 kg/m³

The given parameters;

mass of the solid in air, Ma = 237.5 g

mass of the solid in liquid, Ms = 12.5 g

density of the liquid, $\rho_l = 900 \ kg/m^3$

(i) The density of the solid is calculated as follows;

Weight in air - Weight in liquid = upthrust

$\frac{\rho_o}{\rho_l} = \frac{Ma}{M_a - Ms} \\\\\frac{\rho_o}{900} = \frac{237.5}{237.5 - 12.5}\\\\\frac{\rho_o}{900} =1.0556\\\\\rho_o = 1.0556 \times 900\\\\\rho_o = 950 \ kg/m^3$

(ii) the density of another liquid in which the same solid would float with one-fifth of its volume exposed above the liquid surface.​

This is a low density liquid, because one-fifth of the solid is above the liquid surface while four-fifth is below the liquid surface.

the specific gravity of the liquid = ¹/₅ = 0.2

density of water , $\rho_w = 1000 \ kg/m^3$

$S.G = \frac{\rho_l}{\rho_w} \\\\0.2 = \frac{\rho_l}{1000} \\\\\rho_l = 0.2 \times 1000\\\\\rho_l = 200 \ kg/m^3$

Thus, the density of another liquid in which the same solid would float is 200 kg/m³

Learn more here: brainly.com/question/14400760