Most likely the answer is B.
Formula for orbital speed, v = √(GM/R)
Where G is the universal gravitational constant, M = Central Mass,
R = Distance between centers of Mass.
Given. v = 68 m/s, M = ? , R = 410 km = 410000 m., G = 6.674 * 10⁻¹¹ Nm²/kg²
68 = √(GM/R)
68 = √(6.674 * 10⁻¹¹ * M/410000)
68² = (6.674 * 10⁻¹¹ * M)/410000
(68² * 410000) / 6.674 * 10⁻¹¹ = M
2.84 × 10¹⁹ = M
Mass of Planet Y = 2.84 × 10¹⁹ kg
Answer:
391.5 J
Explanation:
The amount of work done can be calculated using the formula:
- W = F║d
- where the force is parallel to the displacement
Looking at the formula, we can see that the mass of the object does not affect the work done on it.
Substitute the force applied and the displacement of the object into the equation.
- W = (87 N)(4.5 m)
- W = 391.5 J
The amount of work done on the object is 391.5 J in order to move it 4.5 meters with an applied force of 87 Newtons.
Answer:
Explanation:
After the collision velocity of the particle is (4î - 3ĵ)m/s . ... A particle of mass 1 kg moving with a velocity of (4i^−3j^)m/s collides with a fixed surface. ... Perfectly inelastic. D ... The common velocity of the blocks after collision is: ... A ball falls from a height of 5 m and strikes the roof of a lift. ... Stay upto date with our Newsletter! i know this is not right but just here for points see ya loser