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3 years ago

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Consider a continuous time signal, x(t) = ∑ Ai 5 i=1 cos(2πFi t + θi), consisting of a sum of sinusoidal signals of frequencies

100 Hz, 350 Hz, 900 Hz, 1.95 KHz, and 5.35 KHz. Find the discrete time sequence, x(n), obtained by sampling x(t) at a rate of 1.2 KHz. (Note: you must take care of aliasing, if any)

1 answer:

Wewaii [24]3 years ago

4 0

Answer:

duhhhhh

Explanation:

duhhhhh

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A truck’s engine produces 20,000 N of force. It dumps its load and its mass is reduced to 10,000 kg. What is the acceleration of

spayn [35]

Explanation:

If $F = m*a$ , we can easily solve for a.

$a = 20000/10000$

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3 years ago

Find the value of 15.0 n in pounds. use the conversions 1slug=14.59kg and 1ft=0.3048m.

Wewaii [24]

15 N = 15 kg m / s² =
= 15 · 1/14.59 slug · 1 / 0.3048 =
= 15 · 0.06854 · 3.24254 =
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Answer: 15 N is equal to 3.33 pounds.

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3 years ago

What is a combination of two or more simple machines?

Anna [14]

A compound

Explanation:

A compound machine is the combination of two or more simple machines.

An example is bicycle.

A simple machine is a device that is used to increase the magnitude of force.
It is a basic mechanical unit.
Examples are inclined planes, lever systems, wheel and axle.
A compound machine is a combination of these simple machines.

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3 years ago

Two small nonconducting spheres have a total charge of 90.0 C.

valentina_108 [34]

Answer: (a) Smaller charge is $2.7 \times 10^{-5} C$ and larger charge is $11.7 \times 10^{-5} C$ .

(b) Smaller charge is $-11.4 \times 10^{-5}$ and larger charge is $9.1 \times 10^{-5}$ .

Explanation:

(a) When both the spheres have same charge then force is repulsive in nature as like charges tend to repel each other.

Therefore, total charge on the two non-conducting spheres will be calculated as follows.

$Q_{1} + Q_{2} = 90 \mu \times \frac{10^{-6}C}{1 \muC}$

= $9 \times 10^{-5} C$

Therefore, force between the two spheres will be calculated as follows.

F = $k\frac{Q_{1}Q_{2}}{r^{2}}$

12 N = $\frac{(9 \times 10^{9} Nm^{2}/C^{2})Q_{1}Q_{2}}{(0.28 m^{2})}$

$Q_{1}Q_{2} = 0.104 \times 10^{-9} C^{2}$

or, $Q_{1}(9 \times 10^{-5} - Q_{1}) = 0.104 \times 10^{-9} C^{2}$

$9 \times 10^{-5}Q_{1} - Q^{2}_{1} = 0.104 \times 10^{-9} C^{2}$

$Q^{2}_{1} - 9 \times 10^{-5}Q_{1} + 0.104 \times 10^{-9} = 0$

$Q_{1} = 11.7 \times 10^{-5} C, 2.7 \times 10^{-5} C$

This means that smaller charge is $2.7 \times 10^{-5} C$ and larger charge is $11.7 \times 10^{-5} C$ .

(b) When force is attractive in nature then it means both the charges are of opposite sign.

Hence, total charge on the non-conducting sphere is as follows.

$Q_{1} + (-Q_{2}) = 90 \mu \times \frac{10^{-6}C}{1 \muC}$

$Q_{1} - Q_{2} = 9 \times 10^{-5} C$

Now, force between the two spheres is calculated as follows.

F = $k\frac{Q_{1}Q_{2}}{r^{2}}$

12 N = $\frac{(9 \times 10^{9} Nm^{2}/C^{2})Q_{1}Q_{2}}{(0.28 m^{2})}$

$Q_{1}Q_{2} = 0.104 \times 10^{-9} C^{2}$

$Q_{1}(Q_{1} - 9 \times 10^{-5}) = 0.104 \times 10^{-9} C^{2}$

$Q^{2}_{1} - 9 \times 10^{-5}Q_{1} = 0.104 \times 10^{-9} C^{2}$

$Q_{1} = -11.4 \times 10^{-5}, 9.1 \times 10^{-5}$

Hence, smaller charge is $-11.4 \times 10^{-5}$ and larger charge is $9.1 \times 10^{-5}$ .

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3 years ago

Classify the chemical equations as being balanced or not balanced.

ruslelena [56]

1) Balanced
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3 years ago

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