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3 years ago

Why is the following equation invalid? Al + 202 → Al2O3

Chemistry

2 answers:

Ket [755]3 years ago

7 0

Answer:

C. The equation violates the Law of Conservation of Mass

Explanation:

This equation is invalid because it violated the Law of conservation of Mass. The correct option is C.

This law establishes that the mass is not preserved or destroyed, but transformed.

That is why in a chemical reaction, the number of atoms involved in the reagents and products must be equal.

to achieve this it is necessary to perform a reaction adjustment.

The correct equation would be:

$2Al + 3O_{2}$ ⇄ $2Al_{2} O_{3}$

AVprozaik [17]3 years ago

3 0

Answer:

The answer is not in fact c, but D. The reason it's D, is because I turned in my work and saw the answer.

Explanation:

P.S Do not listen to the other persons responce, because I got it wrong. That why I'm here to warn you guys.

Also make sure to follow me

_.queens_spammm_account._

and

fanglin6255

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yKpoI14uk [10]

Answer:sulfer by itself is not pleasant and it can be dangerous by itself but in large amounts.

Explanation:

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3 years ago

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What is NH3+HCl > NH4Cl as a balanced equation

Leno4ka [110]

It’s already balanced

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3 years ago

Which of the following is required to change the state of matter?

nignag [31]

Since there are no given items, I will give a general answer. Energy....or the lack of it. Examples: Heat, electricity, force (when an item is moving and it impacts something, it heats up...friction is an example of this), etc

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3 years ago

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If 4.55 mol of calcium carbide (CaC2) reacts with an excess of water, how many moles of acetylene (C2H2), a gas used in welding,

Rina8888 [55]

Answer:

4.55 mol of C₂H₂

Explanation:

Let's verify the reaction:

CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂

Ratio is 1:1, so 1 mol of calcium carbide will produce 1 mol of acetylene.

4.55 mol of CaC₂ will make the same amount of C₂H₂

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4 years ago

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The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?

siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = $K_a=1.9\times 10^{-5}$

The equilibrium reaction for dissociation of $HN_3$ (weak acid) is,

$HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+$

initially conc. c 0 0

At eqm. $c(1-\alpha)$ $c\alpha$ $c\alpha$

Dissociation constant is given as:

$K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}$

$1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}$

By solving the terms, we get value of $(\alpha)}$

$\alpha=0.00686832$

No we have to calculate the concentration of hydronium ion or hydrogen ion.

$[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M$

Now we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.002747)$

$pH=2.56$

Therefore, the pH of the solution is, 2.56.

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4 years ago