At 500 K the reaction 2 NO(g) + Cl2(g) ⇌ 2 NOCl(g) has Kp = 51 In an equilibrium mixture at 500 K, the partial pressure of NO is
0.125 atm and Cl2 is 0.165 atm. What is the partial pressure of NOCl in the equilibrium mixture?
1 answer:
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Answer:
The empirical formula is C₂H₃
Explanation:
The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound.
The reaction of combustion for a CₐHₓ is:
CₐHₓ + (a+x/4) O₂ → a CO₂ + ˣ/₂ H₂O
The moles obtained are
15,3 g of CO₂ × = 0,3476 moles of CO₂≡moles of C
4,70 g of H₂O × = 0,2608 moles of H₂O × 2 = 0,5216 moles of H.
The ratio H:C is 0,5216/0,3476= 1,5. That means you have 1,5 H per 1C, that is the same than 3H per 2C. Thus, empirical formula is:
C₂H₃
I hope it helps!
Answer:
All hydrogens are in same environment. Hence it will not split which shows as singlet for 4 hydrogen
Explanation:
check the attachment for further explanations
