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Artemon [7]
2 years ago
9

A scientist is working in a lab and accidentally combines two liquids that quickly form a solution. Which process could be used

to
separate the two liquids? (1 point)
heating the liquids and letting one boil away first
passing the liquids through a filter to collect one of them
collecting one of the liquids with a spoon
waiting for the two liquids to separate
Chemistry
1 answer:
lions [1.4K]2 years ago
7 0

Answer:

Heating the liquids and letting one boil away first :)

Explanation:

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Consider the titration of 1L of 0.36 M NH3 (Kb=1.8x10−5) with 0.74 M HCl. What is the pH at the equivalence point of the titrati
worty [1.4K]

Answer:

C

Explanation:

The question asks to calculate the pH at equivalence point of the titration between ammonia and hydrochloric acid

Firstly, we write the equation of reaction between ammonia and hydrochloric acid.

NH3(aq)+HCl(aq)→NH4Cl(aq)

Ionically:

HCl + NH3 ---> NH4  +  Cl-

Firstly, we calculate the number of moles of  the ammonia  as follows:

from c = n/v and thus, n = cv = 0.36 × 1 = 0.36 moles

At the equivalence point, there is equal number of moles of ammonia and HCl.

Hence, volume of HCl = number of moles/molarity of HCl = 0.36/0.74 = 0.486L

Hence, the total volume of solution will be 1 + 0.486 = 1.486L

Now, we calculate the concentration of the ammonium ions = 0.36/1.486 = 0.242M

An ICE TABLE IS USED TO FIND THE CONCENTRATION OF THE HYDROXONIUM ION(H3O+). ICE STANDS FOR INITIAL, CHANGE AND EQUILIBRIUM.

                 NH4+      H2O     ⇄  NH3        H3O+

I                0.242                           0             0

C                 -X                              +x              +X

E             0.242-X                          X              X

Since the question provides us with the base dissociation constant value K b, we can calculate the acid dissociation constant value Ka

To find this, we use the mathematical equation below

K a ⋅ K b    = K w

 

, where  K w- the self-ionization constant of water, equal to  

10 ^-14  at room temperature

This means that you have

K a = K w.K b   = 10 ^− 14 /1.8 * 10^-5 =  5.56 * 10^-10

Ka = [NH3][H3O+]/[NH4+]

= x * x/(0.242-x)

Since the value of Ka is small, we can say that 0.242-x ≈  0.242

Hence, K a = x^2/0.242 = 5.56 * 10^-10

x^2 = 0.242 * 5.56 * 10^-10 = 1.35 * 10^-10

x = 0.00001161895

[H3O+] = 0.00001161895

pH = -log[H3O+]

pH = -log[0.00001161895 ] = 4.94

7 0
3 years ago
Lee and some other students working with Dr. Yung were conducting an experiment and ended up with some confusing results. In the
Alinara [238K]

Answer:

chung long

Explanation:

cause 3 plus 2 =9

6 0
3 years ago
Read 2 more answers
HRISTINA HERRERA: Attempt 1
Lunna [17]

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

7.5+50=57.5\ \text{g}

Products

57.5\ \text{g}

The data is consistent with the law of conservation of matter.

Reactants

50+243=293\ \text{g}

Products

206+97=303\ \text{g}

The data is not consistent with the law of conservation of matter.

Reactant

17.7+34.7=52.4\ \text{g}

Products

62.4\ \text{g}

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

8 0
3 years ago
The combustion of hydrogen and oxygen is commonly used to
posledela

Answer:

6.66 mol

Explanation:

(atm x L) ÷  (0.0821 x K)

(0.875 x 250) ÷  (0.0821 x 400)

=6.66108

5 0
3 years ago
Use the activity series below to predict the products of each of the following reactions. Do not worry about
myrzilka [38]

Answer:

i) CCl₄ and Br₂ does not react

ii) CBr₄ + Cl₂ → CCl₄ + Br₂

Explanation:

i) CCl₄ + Br₂ (no reaction)

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CCl₄ + Br₂ will not have a reaction as the propensity for the chlorine to stay combined with the carbon is higher than the ability for bromine to remain combined with or attract the carbon. Therefore, for CCl₄ + Br₂ there is no reaction

ii) CBr₄ + Cl₂

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CBr₄ + Cl₂ will give products that will have the Br in the CBr₄ replaced by the Cl₂ as follows;

CBr₄ + Cl₂ → CCl₄ + Br₂

The products of the reaction of CBr₄ and Cl₂ are therefore CBr₄ and Cl₂.

8 0
3 years ago
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