A circle has central angle measuring 2pi/5 radians that intersects an arc of length 20cm what is the length of the radius of the
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Answer:
X = 25
Step-by-step explanation:
To solve this question, we'll first of all find determine the side length of the triangle from the perimeter.
Perimeter of an equilaterial triangle = 3 * s
S = side length
Perimeter = 150cm
150 = 3s
S = 150 / 3
S = 50cm
The side lengths are 50cm each since they are all equal.
To find x,
We have to divide the triangle equally into two different part.
Check the first attachment for better illustration on how the equilaterial triangle is.
Check the second attachment for better illustration on the triangle when its divided into a right angle triangle.
From the right angle triangle, we can use pythagorean theorem to solve for x
a² = b² + c²
a = 50cm
b = 25cm
c = x√(3)
50² = [x√(3)]² + 25²
2500 = x² * 3 + 625
2500 - 625 = 3x²
1875 = 3x²
X² = 1875 / 3
X² = 625
X = √(625)
X = 25
