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4 years ago

Describe what you would observe when potassium reacts with water

Chemistry

1 answer:

marissa [1.9K]4 years ago

4 0

When potassium is added to water the metal melts and floats. It moves around very quickly in the surface of the water.

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10. The diagram below shows the sun, Earth, and the moon.

kotykmax [81]

Answer:

I think a lunar eclipse

5 0

3 years ago

Read 2 more answers

What is the heat of reaction H2 + 1/3N2 2/3NH3

laila [671]

Answer;

1/3N(g)+H(g)—>1/3NH3(g)

4 0

3 years ago

Use the ΔHrxn values of the following reactions: 2SO2(g) + O2(g) → 2SO3(g) ΔHrxn = –196 kJ 2S(s) + 3O2(g) → 2SO3(g) ΔHrxn = –790

sesenic [268]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is -297 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$S(s)+O_2(g)\rightarrow SO_2(g)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$ $\Delta H_1=-196kJ$

(2) $2S(g)+3O_2(g)\rightarrow 2SO_3(g)$ $\Delta H_2=-790kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=\frac{[1\times (-\Delta H_1)]+[1\times \Delta H_2]}{2}$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=\frac{[(1\times -(-196))+(1\times (-790))}{2}=-297kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is -297 kJ.

8 0

3 years ago

How many moles of oxygen react with 12 moles of aluminum

mina [271]

Answer:

If, for example, we want to know how many moles of oxygen will react with 17.6 mol ... Write the balanced chemical reaction for the combustion of C 5H 12

Explanation:

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3 years ago

in a sample of silcon 92.21% of the atoms have a mass of 27.98 amu, 4.70% have a mass of 28.98 amu and 3.09% have a mass of 29.9

oksano4ka [1.4K]

Answer: 28.1 amu

Explanation:

Mass of isotope 1 = 27.98 amu

% abundance of isotope 1 = 92.21% = $\frac{92.21}{100}=0.9221$