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mart [117]
3 years ago
10

What is the heat of reaction H2 + 1/3N2 2/3NH3

Chemistry
1 answer:
laila [671]3 years ago
4 0
Answer;

1/3N(g)+H(g)—>1/3NH3(g)
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What would you multiply "moles of oxygen" by to get the units "grams of oxygen"?
photoshop1234 [79]

Answer:

AM

Explanation:

to go from moles to grams you multiply by the Atomic Mass or Molar Mass (Atomic Mass for an element and Molar Mass for a compound).

The formula is:

Mass = moles * MM

6 0
3 years ago
Suppose you need 7.5m of Grade 70 tow chain, which has a diameter of /38" and weighs 2.16/kgm, to tow a car. How would you calcu
lutik1710 [3]

The mass of this much chain is 0.22 grams for  7.5m of Grade 70 tow chain, which has a diameter of /38" and weighs 2.16/kgm, to tow a car.

<h3>What are weight and mass?</h3>

Mass is the amount of the substance and object and the weight is the gravitational force required to act upon the particular mass of the substance.

To calculate the mass of car divide the wight to the gravity value 9.8 meter per second.

                 mass = weight / gravity

substituting the value,  

                     mass = 2.16 / 9.8

                     mass = 0.22 grams

Therefore,7.5m of Grade 70 tow chain, which has a diameter of /38" and weighs 2.16/kgm, to tow a car the mass will be 0.22 grams.

               

Learn more about weight and mass, here:

brainly.com/question/28122305

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8 0
2 years ago
Which of the following reactions will produce a neutral salt?
anzhelika [568]
Strong acid weak base 
7 0
3 years ago
A closed container has 5.60 x 1023 molecules of oxygen gas (O2). How many moles is that?
ozzi
The answer is 5.60 x 1023= 5,728.8
8 0
3 years ago
A chemist needs 500.0 mL of a 1.500 M perchloric acid solution. The stockroom provides the chemist with
Lynna [10]

Answer:-  47.62 mL

Solution:- It is a dilution problem where we are asked to calculate the volume of 15.75 M perchloric acid solution required to make 500.0 mL of 1.500 M solution.

For solving this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 is the concentration of the concentrated solution and V_1 is it's volume.

M_2 is the concentration of the diluted solution and V_2 is it's volume.  Let's plug in the values in the equation and solve it for V_1 .

15.75M(V_1)=1.500M(500.0mL)

On rearranging this for V_1 :

V_1=\frac{1.500M(500.0mL)}{15.75M}

V_1=47.60mL

So, 47.62 mL of 15.75 M perchloric acid are required to make 500.0mL of 1.500 M solution.

3 0
4 years ago
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