Answer:
the empirical formula of the metal fluoride.
Explanation:
Mass of copper heated = 8.249 g
Mass of copper fluoride formed = 13.18 g
Mass of fluorine gas in copper fluoride = x
Moles of copper :
Moles of fluorine:
For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.
The empirical formula of the copper fluoride =
the empirical formula of the metal fluoride.
M (NaCl) = n × M = 3.75 × 58.5 =
219.375 g
M (NaCl) = 23 + 35.5 = 58.5 g/mol
Answer is:
1) lubricant - 500 ppm by weight.
2) moisture - 50 ppm by weight.
3) non-condensable gases (air) - 150 ppm by weight.
Standard J2099 specific the maximum levels of contaminants for R134a.
ppm<span> (parts-per-million, </span>10⁻⁶) is <span>value that represents the part of a whole number in units of 1/1000000.</span>
The strong Base with a pH of 12 is reduced by 4 units upon being added with solution Y. If you added a strong acid to the strong base, all ions are present in the solution, yes? So every OH- is neutralised by every H+ for example, meaning the resultant pH should be 7. The resultant pH is only 8 however, so solution Y must be a <em>weak acid </em>only!
