d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Answer:
I don't know the answer to the question but I just wanted to say I love your profile picture. I love Quackity :) <3
I'm pretty sure it is 155
Hey there Altagraciasouth :)
Significant Figure Question:
**Question 4162 to 3 SF
Explanation:
We first have to look for the third number in 4162. That would be 62!
So we round 62 to the nearest ten. Which gives us 60!
**Answer: 4160
Hope this helped :)
I would think it is b sorry if im wrong
