Answer:
two real, unequal roots
Step-by-step explanation:
This is a quadratic equation. The quadratic formula can be used to determine how many and what kind of roots may exist:
Find the discriminant, which is defined as b^2 - 4ac, if ax^2 + bx + c = 0. In this case, a = 1, b = -2 and c = -8, so that the discriminant value is
(-2)^2 - 4(1)(-8), or 4 + 32 = 36.
Because the discriminant is real and positive, we know for certain that we have two real, unequal roots
Answer:
62 i think
Step-by-step explanation:
Answer:
Step-by-step explanation:
The function must be factorable.
For example, x^2 + x - 6= 0 factors to (x + 3)(x - 2) = 0 so the roots are -3 and 2.
x^2 + x - 7 = 0 will not factor so you need another method to solve this.
Answer:
All corresponding sides and angles will be congruent
Step-by-step explanation:
Answer:
It's 8
Step-by-step explanation:
![16 ^{ \frac{3}{4} } = \sqrt[4]{16 ^{3} } = \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} } = 2^{3} = 8](https://tex.z-dn.net/?f=%2016%20%5E%7B%20%5Cfrac%7B3%7D%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B16%20%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B2%20%5E%7B4%20%5Ctimes%203%7D%20%7D%20%3D%202%5E%7B%20%5Cfrac%7B12%7D%7B4%7D%20%7D%20%20%20%3D%202%5E%7B3%7D%20%20%3D%208)
