Answer:
150mL
Explanation:
First, let us calculate the volume of the diluted solution. This is illustrated below:
Information obtained from the question include:
V1 (initial volume) = 50mL
C1 (initial concentration) = 1M
C2 (final concentration) = 0.25M
V2 (final volume) =.?
The volume of the diluted solution can be obtained using the dilution formula C1V1 = C2V2 as shown below:
C1V1 = C2V2
1 x 50 = 0.25 x V2
Divide both side by 0.25
V2 = 50/0.25
V2 = 200mL
The volume of the diluted solution is 200mL.
Now, to obtain the volume of the water added to the solution, we'll simply subtract the initial volume from the final volume as shown below
Volume of water added = V2 - V1
Volume of water added = 200 - 50
Volume of water added = 150mL
Therefore, the volume of water added is 150mL
Answer:
mass of water, mw = 300g = 0.3kg
∆Tw = (80 - 20) °C
volume of air, va = 100m³
mass of air, ma = 100g = 0.1kg
∆Ta = ?
H = mc∆T
Hw = mwcw∆Tw
Hw = 0.3*4200*60
Hw = 75600J
Hw = 75.6 kJ
All the above heat energy got absorbed by air,
that is; Ha = 75600J
since it's given that the heat was absorbed by a specific amount of volume of air
then specific capacity of volume of air is
then,
ca = <u>Ha</u><u> </u> × <u>density</u><u> </u>
ma temp
then,
Ha = vaca∆Ta
where, ca = volumetric heat capacity of air = 0.012kJ/m³°C
75.6kJ = 100m³ × 0.012kJ/m³°C × ∆Ta
75.6 = 1.2/°C × ∆Ta
∆Ta = 63°C
63°C is the temperature change in air.
1) Endothermic
2) Heat absorbed by reaction = 2511.6J
3)ΔH_rxn = 18.2 kJ/ mol
Explanation:
Mass of KCl = 10.3 g
Moles of KCl = mass of KCl / molar mass of KCl
= 10.3 g / 74.5513 g/mol
=0.138 mol
Mass of water, m = 200 g
Specific heat of water, C= 4.186 Jg^-1°C^-1
T_initial = 22.0C
T_final = 19.0°C
ΔT = T_final - T_initial
=19.0°C - 22.0°C
= -3.0°C
Heat absorbed = Heat released
q_rxn =-q_water
so,
q_water = m CΔT
substitute
q_water = 200g * 4.186J g^-1 °C^-1 *(-3.0°C)
= -2511.6J
Heat absorbed by reaction = 2511.6J
q_rxn = -q_water = 2511.6J
ΔH_rxn = q_rxn /moles of KCl
=2511.6J / 0.138 mol
ΔH_rxn =18.2kJ / mol
The reaction is a endothermic reaction.
MgSO4 + 2NaOH —> Mg(OH)2 + Na2SO4
Lithium, Chlorine, and Oxygen
hope this helped :)