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podryga [215]
3 years ago
8

Predict what will be observed in each experiment below. experimentpredicted observation (choose one) A student sees tiny bubbles

clinging to the inside of an unopened plastic bottle full of carbonated soft drink. The student squeezes the bottle. The bubbles will shrink, and some may vanish. The bubbles will grow, and more may appear. The bubbles won't change. I need more information to predict what will happen to the bubbles. A pair of samples of water are taken from a well bored into a large underground salt deposit. Sample
Chemistry
1 answer:
Andrew [12]3 years ago
5 0

Answer:

The bubbles will grow, and more may appear.

Explanation:

The bubble seen in a carbonated soft drink are bubbles of CO2. These bubbles appear because the gas is dissolved under pressure in carbonated drinks.

If i squeeze the bottle, i am applying more pressure to the bottle hence more bubbles will appear in the bottle under this increased pressure.

Hence, if the student squeezes the bottle, the bubbles will grow, and more may appear.

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Which compounds are distinguished by an oxygen bridge between two carbon chains?
sergiy2304 [10]
I think ethers are being referred to in this questions since an ether is defined by having a oxygen atom that is directly bonded to carbons on both sides.

I hope this helps.  Let me know if you any further questions or if you anything to be clarified.
3 0
3 years ago
Generally, what happens to the rate of dissolution for a solid solute when you change from stirring a solution to not stirring i
Alex Ar [27]

Answer:

The rate of dissolution for a solid solute when cease of stirring is typically: B. It is decreased

Explanation:

The rate of dissolution for a solid solute decreases when you stop stirring it.

6 0
3 years ago
What amount of heat energy is required to raise the temperature of 152 g of water from 24 °C to 74 °C.
DIA [1.3K]

Answer:

Q = 31798.4J = 31.79kJ

Explanation:

Heat energy (Q) = ?

Mass (m) = 152g

T1 = 24°C

T2 = 74°C

Specific heat capacity of water (c) = 4.184J/g°C

Q = Mc∇T

Q = 152 * 4.184 * (74 - 24)

Q = 635.968 * 50

Q = 31798.4J

Q = 31.79kJ

Heat required is 31.79kJ

6 0
3 years ago
Rachel burns a 53 gram cracker under a soda can filled with 81.6 grams of water. She took the temperature of the water before sh
Anna11 [10]

Answer

Q=4479.8 cal

Procedure

To solve the problem you will need to use the specific heat formula

Q=mc\Delta T

Where;

Q=heat energy

m=mass

c=specific heat capacity

ΔT=change in temperature

Assuming that the heat released from the cracker of unknown material is equal to the heat absorbed by the water, then we can use the c and m for water in our calculations.

c_{water}=4.186\frac{J}{g\degree C}

Substituting the values in our equation we have

Q=mc\Delta T=81.6\text{ }g(4.186\frac{J}{g\degree C})(68.1-13.2)\degree C=18752.61\text{ }J

Finally, transform the J to cal

18752.61\text{ }J\frac{1\text{ }cal}{4.186\text{ }J}=4479.8\text{ cal}

8 0
1 year ago
What volume of 0.10 M NaOH is required to neutralize 30 mL of 0.10 M HCl?
coldgirl [10]
30 mL. The two compounds need to balance each other out.
5 0
3 years ago
Read 2 more answers
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