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Reil [10]
3 years ago
7

30 POINTS TO WHOEVER ANSWERS!!!

Chemistry
1 answer:
Ratling [72]3 years ago
3 0

Answer:

Cell

Explanation: An atom is smaller, but isn't a living organism, so the second smallest would be cell.

You might be interested in
What is the lower concentration limit (vol%) at which a mixture of ethanol in air can explode?
liubo4ka [24]

Answer:

Lower explosive limit (LEL) of ethanol = 3.3%

Explanation:

In the case of alcohol, ethanol presents certain fire hazards. Its momentary flash point is 55ºF (12.9ºC), while the momentary flash point of gasoline is -45ºF (-42.8ºC), and the E85 mixture ranges between -20ºF and -4ºF (between -28 , 9ºC and -20ºC), and has a wider range of flammability limits than gasoline. For emergency response teams, this implies that during a release of the typical ethanol / gasoline mixture, the fuel can be expected to behave like gasoline: It is heavier than air - as we mentioned earlier - and can produce vapors and form flammable mixtures in the air, under most environmental conditions.

General properties and comparison with other inflambles products:

Flash point momentary Gasoline = -45 ° F

<u>Ethanol</u> = 55 ° F

E 85 = between -20º and -4º F

<u>Flammability limits </u>

Lower explosive limit (LEL) of ethanol = 3.3%

Upper Explosive Limit (UEL) = 19%

Lower explosive limit (LEL) of the mixture E 85 = 1.4%

Upper Explosive Limit (UEL) 85 = 19%

Lower explosive limit (LEL) of gasoline = 1.4%

Upper Explosive Limit (UEL) = 7.6%

They have a wider range than gasoline

4 0
3 years ago
HELP ME PLEASE
lions [1.4K]

Answer:

A

Explanation:

Definitely not in the cell theory

3 0
3 years ago
What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?
mr Goodwill [35]

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we <u>convert 166.00 g of KI into moles</u>, using its <em>molar mass</em>:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

  • 166.00 g ÷ 166 g/mol = 1 mol KI

Then we <u>calculate the required volume</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters

Liters = moles / molarity

  • 1 mol / 1.00 M = 1 L
3 0
3 years ago
For the reaction: 3 H2(g) + N2(g) &lt;--&gt; 2 NH3(g), the concentrations at equilbrium were [H2] = 0.10 M, [N2] = 0.10 M, and [
masya89 [10]

The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵

<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>

It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.

Hence, the equilibrium constant of the reaction in discuss is;

K = [5.6]²/[0.10]³[0.10]

k = 5.6² × 10⁴

k = 3.136 × 10⁵

K = 3.1 × 10⁵.

Read more on equilibrium constant;

brainly.com/question/1619133

#SPJ1

5 0
2 years ago
Do nonmetals form anions or cations?
MrRa [10]
Since medals form cations
nonmedals form anions
8 0
3 years ago
Read 2 more answers
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