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Savatey [412]
3 years ago
15

a circus performer is shot of a cannon and into a net with an acceleration of 1.5g. what is her acceleration in meters per secon

d squared when she hits the net?
Physics
2 answers:
TiliK225 [7]3 years ago
6 0
G→Acceleration due to gravity=9.8m<span>s<span>−2</span></span>

So

<span>Acceleration of performer=1.5g=1.5×9.8m<span>s<span>−2</span></span>=14.7m<span>s<span>−<span>2</span></span></span></span>

rosijanka [135]3 years ago
6 0

Answer:

The answer is 14.7m / s2

Explanation:

Hello! Let's solve this!

First we write the data we have

acceleration (a) = 1.5g

We know that the acceleration of gravity is g = 9.8m / s2

Acceleration when it hits the wall is

a = 1.5 * g = 1.5 * 9.8m / s2 = 14.7m / s2

The answer is 14.7m / s2

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Normal atmospheric pressure is 1.013 105 Pa. The approach of a storm causes the height of a mercury barometer to drop by 27.1 mm
Burka [1]

Answer:

The atmospheric pressure is 0.97622\times10^{5}\ Pa.

Explanation:

Given that,

Atmospheric pressure P_{atm}= 1.013\times10^{5}\ Pa    

drop height h'= 27.1 mm

Density of mercury \rho= 13.59 g/cm^3

We need to calculate the height

Using formula of pressure

p = \rho g h

Put the value into the formula

1.013\times10^{5}=13.59\times10^{3}\times9.8\times h

h =\dfrac{1.013\times10^{5}}{13.59\times10^{3}\times9.8}

h=0.76\ m

We need to calculate the new height

h''=h - h'

h''=0.76-27.1\times10^{-3}

h''=0.76-0.027

h''=0.733\ m

We need to calculate the atmospheric pressure

Using formula of atmospheric pressure

P=\rho g h

Put the value into the formula

P= 13.59\times10^{3}\times9.8\times0.733

P=0.97622\times10^{5}\ Pa

Hence, The atmospheric pressure is 0.97622\times10^{5}\ Pa.

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Answer:

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