Answer:
The Internet (social media to be precise)
Explanation:
False science are purported scientific conclusions drawn without any scientific data or procedures followed to arrive at such conclusions. These purported conclusions would have been irrelevant or not widespread without the internet or social media but the easy accessibility to social media globally has made "everyone" to be a scientist or even a publisher without scientific steps.
Some innocent individuals also help share (on the internet) these false science because of the inability to differentiate between the real scientific process and the ones done without any/some due scientific processes hence assisting in promoting these false science unknowingly. If there were no internet, these false sciences would not be this widespread as information will not travel this fast.
Outcome- possible results of an experiment is called an outcome.
ex- 2 is a possible outcome when a number cube is rolled
Answer:
q=6.22*10^-10C
Explanation:
Two large metal plates of area 0.88 m2 face each other, 4.8 cm apart, with equal charge magnitudes but opposite signs. The field magnitude E between them (neglect fringing) is 80 N/C. Find |q|
E=α/∈, electric field within the plate
α=q/A
A=area of the plate
∈=is the permittivity
substituting , we have
The field magnitude E between them (neglect fringing)
E=q/A∈
q=EA∈
q=0.88*80*8.84*10^-12
q=6.22*10^-10C
Answer:
The maximum compression of the spring after the collision is 0.15 m
Explanation:
Given data
Mass of the block (m) = 0.80 kg
Initial velocity (v) = 1.2 m/s
Spring constant (k) = 50 N/m
Find the maximum compression of the spring (x) after compression
Potential energy of the spring = Kinetic energy of the block
Kinetic energy of the block = 0.5 × (mv)²
Kinetic energy of the block = 0.5 × (0.80 × 1.2)²
Kinetic energy of the block =0.5 × 0.9216
Kinetic energy of the block = 0.4608 ---------->(1)
Potential energy of the spring = 0.5 × k × x²
Potential energy of the spring = 0.5 × 50 × x²
Potential energy of the spring = 25 x² ---------> (2)
Equate (1) and (2)
25 x² = 0.4608
x² = 0.018432 m²
x =0.1357 = 0.15 m
Therefore the maximum compression of the spring after collision is 0.15 m