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Luda [366]
3 years ago
11

If Thomson’s atomic theory was accurate, what would the results of Rutherford’s gold foil experiment have been?

Physics
1 answer:
Akimi4 [234]3 years ago
3 0

Answer:

If Thomson's atomic theory was accurate, the positively charged particles would have gone through the foil. The balanced positive charges and negative charges within the atom would have made the atom neutral, and the positive charges would not have been concentrated enough to cause deflection.

Explanation:

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Terra tosses a 0.20 kg volleyball straight up at 10.0 m/s. how high does it go?
Sliva [168]

Answer:

5.1 meters

Explanation:

Terra tosses a 0.20kg volleyball up at at a speed of 10 m/s

The height can be calculated as follows

= v^2/2g

= 10^2/2×9.8

= 100/19.6

= 5.1 meters

Hence the height is 5.1 meters

5 0
3 years ago
Average distance of 160.0 cm. Its average time was 5.74 seconds. What is its average speed?
Gre4nikov [31]
Your answer is .279m/s
5 0
3 years ago
Which two processes are responsible for water's transfer of energy in the atmosphere and hydrosphere
Varvara68 [4.7K]
I found the Hydrolic system, im not sire if its helpful or not. I could only find that one, sorry if it doesn't help but I hope it does ^-^
3 0
3 years ago
The magnetic field at 8 cm distance from a long straight wire, carrying is 0.2x10^-5 T. How much is the electric current in the
FrozenT [24]

Answer:

The electric current in the wire is 0.8 A

Explanation:

We solve this problem by applying the formula of the magnetic field generated at a distance by a long and straight conductor wire that carries electric current, as follows:

B=\frac{2\pi*a }{u*I}

B= Magnetic field due to a straight and long wire that carries current

u= Free space permeability

I= Electrical current passing through the wire

a  = Perpendicular distance from the wire to the point where the magnetic field is located

Magnetic Field Calculation

We cleared (I) of the formula (1):

I=\frac{2\pi*a*B }{u} Formula(2)

B=0.2*10^{-5}  T = 0.2*10^{-5} \frac{weber}{m^{2} }

a  =8cm=0.08m

u=4*\pi *10^{-7} \frac{Weber}{A*m}

We replace the known information in the formula (2)

I=\frac{2\pi*0.08*0.2*10^{-5}  }{4\pi *10x^{-7} }

I=0.8 A

Answer: The electric current in the wire is 0.8 A

4 0
3 years ago
Find the intensity of a 55 dB sound given I 0=10^-12W/m^2
MakcuM [25]

Answer:

3.16 × 10^{-7} W/m^{2}

Explanation:

β(dB)=10 × log_{10}(\frac{I}{I_{0} })

I_{0}=10^{-12} W/m^{2}

β=55 dB

Therefore plugging into the equation the values,

55=10 log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

5.5= log_{10}(\frac{I}{ [tex]10^{-12}})[/tex]

10^{5.5}= \frac{I}{10^{-12} }

316227.76×10^{-12}= I

I= 3.16 × 10^{-7} W/m^{2}

5 0
3 years ago
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