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gavmur [86]
3 years ago
15

Suppose a car travels at a constant speed of 12.0 m/s. How far would it move in 3600.0 s?

Physics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

43200 m

Explanation:

speed = 12.0 m/s

time = 3600.0 s

distance = speed * time

distance = 12.0 m/s * 3600.0 s

distance = 43200 m

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gogolik [260]

Answer:

B) Within an atom, an electron can have only particular energies.

Explanation:

As we know that electrons have energy but apart from electrons we know that protons and neutrons inside the nucleus of atom will also have energy in them.

rest all the statements are true as we have

A) Electrons orbit the nucleus rather like planets orbiting the Sun.

TRUE, because electrons can move in stationary orbit around the nucleus

C) Electrons can jump between energy levels in an atom only if they receive or give up an amount of energy equal to the difference in energy between the energy levels.

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D) An electron has a negative electrical charge.

Charge of an electron is given as -1.6 \times 10^{-19} C

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Which three characteristics describe the energy of a wave? (2 points)
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Answer is B! Hope you have a good day
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Sarah needs to replace part of the metal railing on her deck and wants the new railing to match the existing railing. However, s
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I think the answer could be electrical conductivity
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4 years ago
Read 2 more answers
Please explain what these are and give simple examples if you can:
erma4kov [3.2K]

Answer:

centripetal force- a fore force acts on a body moving in a circular path and is directed towards the center the body is moving

centrifugal force-is a force that acts outward and moving around a center like at six flags and swings tahts fly u in air or the spinning things at the park

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4 0
3 years ago
A 50-turn circular coil with radius 4 cm is placed in magnetic field of 6000 G. An amount of 800 mA current passes through the c
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Explanation:

n=50,r=0.02mn=50,r=0.02m,

I=5AandB=0.20TI=5AandB=0.20T

τismaxiμmwhensinθ=90∘τismaxiμmwhensinθ=90∘

τmax=niabsin90∘=mbτmax=niabsin90∘=mb

=50×5×3.14×4×10−4×2×10−1=50×5×3.14×4×10-4×2×10-1

=6.28×10−2Nm=6.28×10-2Nm

Given τ=12×τmaxτ=12×τmax

⇒sinsinθ=12⇒sinsinθ=12 or sinθ=30∘sinθ=30∘

=∠betweenareavar→randmag≠ticfield=∠betweenareavar→randmag≠ticfield.

So angle between magnetic field and the plane of the coil

=90∘−30∘=60∘=90∘-30∘=60∘.

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