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3 years ago

Is it possible to find density and volume of a substance with just the mass?

1 answer:

7 0

Even though an atom may be smaller than another atom, it might have more mass. The mass of atoms, their size, and how they are arranged determine the density of a substance. Density equals the mass of the object divided by its volume; D = m/v. Objects with the same mass but different volume have different densities.

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List the five major pollutants in the United States

lawyer [7]

Fine particles, ground level ozone, sulfur dioxide, nitrogen dioxide, lead

6 0

3 years ago

What of the following is a Cation?<br> A) (SO3)^-2<br> B) sulfate<br> C) (Ca)^+2<br> D) chloride

Agata [3.3K]

Answer:c

Explanation:

I think because ca^+2

It’s loses the ion and if u look back u would see that a cation is a t charge but it’s not Goan that electron it’s losing that electron

4 0

3 years ago

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

katovenus [111]

Answer:

The new partial pressures after equilibrium is reestablished:

$PCl_3,p_1'=6.798 Torr$

$Cl_2,p_2'=26.398 Torr$

$PCl_5,p_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=p_1=13.2 Torr$

Partial pressure of the $Cl_2=p_2=13.2 Torr$

Partial pressure of the $PCl_5=p_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{p_1}{p_1\times p_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=p_1'=13.2 Torr$

Partial pressure of the $Cl_2=p_2'=?$

Partial pressure of the $PCl_5=p_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=p_1'+p_2'+p_3'$

$263.0Torr=13.2 Torr+p_2'+217.0 Torr$

$p_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{p_3'}{p_1'\times p_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished:

$p_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

$p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

$p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

6 0

3 years ago

Which types of orbitals are found in the principal energy level n = 2?

AfilCa [17]

Remember this:

1) n is principal quantum number and represents the energy level.

2) l is the second quantum number and represent the type of orbital.

3) l can take values from 0 to n - 1

4) each number of l is associated with a type of orbital. This table shows the equivalence:

l number       type of orbital

0                    s

1                    p

2                    d

3                     f

With that, you can tell that n = 2 permits l = 0 and 1, which is orbitals s and p.

Therefore, the answer is the option D) s, p.

3 0

3 years ago

Read 2 more answers

Which has more gravitational potential energy—a book sitting on a desk or the same

nydimaria [60]

Answer:

The book sitting on the desk

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its position relative to the ground.

It is calculated as:

$GPE=mgh$

where

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object with respect to the ground

From the formula, we see that the GPE of an object is directly proportional to the heigth h: so, the higher the location of the object, the larger the GPE.

In this problem, we are comparing a book sitting on a desk and the same book sitting on the floor. In the two situations, the mass of the book is the same; however, in the first case, the value of the height is h, while in the second case, the value of h is lower (because the book is located at a lower height, being on the floor).

Therefore, we can conclude that the first book must have a larger GPE, since it has a larger value of h.

6 0

3 years ago