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bogdanovich [222]
2 years ago
13

Suppose you have samples of three unknown solids. Explain how you could use their properties to

Chemistry
1 answer:
alexandr402 [8]2 years ago
7 0

Answer:https://es.khanacademy.org/science/ap-chemistry-beta/x2eef969c74e0d802:intermolecular-forces-and-properties/x2eef969c74e0d802:properties-of-solids/v/ionic-solids

Explanation:

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A substance that prevents the flow of electric current is a(n) .
nasty-shy [4]
An Insulator.

Insulators prevent flow of electric current. Example is wood, clay.
4 0
3 years ago
Read 2 more answers
An objects tendency to maintain its current state of motion is called
daser333 [38]
Inertia is the tendency of an object to remain at rest or remain in motion. Inertia is related to an object's mass.
3 0
3 years ago
9. A student wished to prepare ethylene gas by dehydration of ethanol at 140oC using sulfuric acid as the dehydrating agent. A l
Arte-miy333 [17]

We have that the the liquid is

  • C_2H_5OH (ethanol
  • And at a condition of H_2SO4 as catalyst and temp 170

From the question we are told

  • A student wished to prepare <em>ethylene </em>gas by <em>dehydration </em>of ethanol at 140oC using sulfuric acid as the <em>dehydrating </em>agent.
  • A low-boiling liquid was obtained instead of ethylene.
  • What was the liquid, and how might the reaction conditions be changed to give ethylene

<h3>Ethylene formation</h3>

Generally the equation is

2C_2H_5OH------CH3CH_2O-CH_2CH_3+H_20

Therefore

with ethanol at 140oC

The product is diethyl ethen

The reaction at 170 ethylene will give

C_2H_5OH-------CH_2=CH_2+H_2O( at a condition of H_2SO4 as catalyst and temp 170)

Therefore

The the liquid is

  • C_2H_5OH (ethanol

For more information on Ethylene visit

brainly.com/question/20117360

8 0
2 years ago
A substance that can be broken down and recycled by bacteria and other decomposes is said to be__________
Stells [14]

Answer:The substance is Biodegradable

Explanation:

When something is biodegradable it can be broken down by organical processes or decomposers.

6 0
3 years ago
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
2 years ago
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