3.6 grams because I searched it up and that’s what it said
Part 1 : Answer is only B substance is soluble in water.
In this experiment undissolved mass of each substance was measured. According to the given data, undissolved mass of substance B at 20 °C is 10 g while A is 50 g. Since, the initial added mass of each substance is 50 g, we can see that substance A is not soluble in water since the undissolved mass is 50 g.
Part 2 : Substance A is not soluble in water and substance B is soluble in water.
According to the given data, the undissolved mass of substance A remains as same as initial added mass, 50 g throughout the temperature range from 20 ° to 80 °C. Hence, we can conclude that substance A is not soluble in water.
But, according to the data, undissolved mass of substance B at 20 °C is 10 g. That means, 40 g of substance B was dissolved in water. When the temperature increases the undissolved mass of substance B decreases. Hence, we can conclude that substance B is soluble in water and solubility increases with temperature.
The proton is 1
Electron is 1/1840
The neutron is 1
Answer:
37.046 grams of oxygen gas were produced.
Explanation:
Moles of potassium chlorite =
According to reaction 2 moles of potassium chlorite gives 3 moles of oxygen gas.
Then 0.7718 moles of potassium chlorite will give:
of oxygen gas.
Mass of 1.1577 moles of oxygen gas:
1.1577 mol × 32 g/mol = 37.046 g
37.046 grams of oxygen gas were produced.
Answer:
1.67 moles of N2 produce 2.5moles of NaN3
Explanation:
Equation of reaction:
2Na + 3N₂ → 2NaN₃
From the equation of reaction, 3 moles of N₂ produces 2 moles of NaN₃
How much is gotten from 2.5moles of 2NaN₃?
2 moles of N₂ = 3 moles of NaN₃
X moles of N₂ = 2.5 moles of NaN₃
X = (2.5 × 2) / 3
X = 1.67moles of N₂
1.67 moles of N₂ produces 2.5moles of NaN₃