Answer:
27oz
Explanation:
Let the volume quantity of the 10% solution = x
The volume quantity of the 15% alcohol solution is known as = 18oz
Therefore the volume of the 12% product = 18oz + x
Therefore
0.10 × x + 0.15 × 18oz = 0.12 × (18oz+x)
0.15×18oz - 0.12×18oz = 0.12×x - 0.10×x
.
0.03*18oz = 0.02x
Dividing both sides by 0.02
x = 27oz
Verifying the answer, we have
0.1 × 27 + 18 × 0.15 = 0.12 × 45
2.7 + 2.7 = 5.4
Answer:
208.7°C was the initial temperature of the limestone.
Explanation:
Heat lost by limestone will be equal to heat gained by the water
Mass of limestone = 
Specific heat capacity of limestone = 
Initial temperature of the limestone = 
Final temperature = 
=T = 51.9°C
Mass of water= 
Specific heat capacity of water= 
Initial temperature of the water = 
Final temperature of water = =T = 51.9°C
On substituting all values:
208.7°C was the initial temperature of the limestone.
It is the polar nature of water that allows ionic compounds to dissolve in it. In the case of sodium chloride (NaCl) for example, the positive sodium ions (Na+) are attracted to the negative pole of the water molecule, while the negative chloride ions (Cl−) are attracted to the positive pole of the water molecule.
Answer:
1) pure water
2) 0.75 m CaCl2
3) 1.0 m NaCl
4) 0.5 m KBr
5) 1.5 m glucose (C6H12O6)
Explanation:
Boiling point elevation is a colligative property. Coligative properties are properties that depend on the amount of solute present in the system. The boiling point of solvents increase due to the presence of solutes.
The boiling point elevation depends on the number of particles the solute forms in solution and the molality of the solute. The more the number of particles formed by the solute and the greater the molality of the solute, the greater the magnitude of boiling point elevation.
The order of decreasing hoping point elevation is;
1) 0.75 m CaCl2
2) 1.0 m NaCl
3) 0.5 m KBr
4) 1.5 m glucose (C6H12O6)
