Answer:
<em><u>Copper </u></em><em><u>(</u></em><em><u>Cu2)</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>Iron </u></em><em><u>(</u></em><em><u>Fe2+</u></em><em><u> </u></em><em><u>Fe3 </u></em><em><u>+</u></em><em><u>)</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>and </u></em><em><u>Hydrogen </u></em><em><u>ion </u></em><em><u>(</u></em><em><u>H+</u></em><em><u>)</u></em>
Explanation:
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C9H20 + 14O2 --> 9CO2 + 10H2O
Ionization energy is the energy required to remove an electron from a gaseous atom or ion. The first or initial ionization energy or Ei of an atom or molecule is the energy required to remove one mole of electrons from one mole of isolated gaseous atoms or ions
Answer:
Explanation:
Word equation:
sulfuric acid + ammonium hydroxide → ammonium sulfate + water
Chemical equation:
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
Balanced chemical equation:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.
Steps to balance the equation:
Steps 1;
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
H = 7 H = 10
S = 1 S = 1
O = 5 O = 5
N = 1 N = 2
Step 2:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O
H = 12 H = 10
S = 1 S = 1
O = 6 O = 5
N = 2 N = 2
Step 3:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
H = 12 H = 12
S = 1 S = 1
O = 6 O = 6
N = 2 N = 2
A.2SO₂ + O₂ + 2H₂O → 2H₂SO₄
B.Moles of SO₂ = 67.2 / 22.4Moles of SO₂ = 3 molesMoles of H₂SO₄ = 3 molesMass of H₂SO₄ = 3 x 98Mass of H₂SO₄ = 294 grams
Assuming sulfuric acid to have the same density as water,density = 1000 g / LVolume = mass / densityVolume = 294 / 1000Volume = 0.29 liters of sulfuric acid