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Roman55 [17]
3 years ago
14

Hydrogen can be obtained economically as a byproduct in the electrolysis of what?

Chemistry
1 answer:
Genrish500 [490]3 years ago
5 0
Hydrogen can be obtained economically as a byproduct in the electrolysis of water. It's mainly obtained in the the manufacture of Chlorine though.
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C. fusion

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in some areas of the earth , the crust is squeezed and pushed upward. this is what process in that it directly forms what?
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A certain mass of hydrogen gas collected over water at 10°C and 750mmHg pressure has a volume of 57cm3. Calculate the volume whe
neonofarm [45]

The volume of gas when it is dry at S.T.P : 53.6 cm³

<h3>Further explanation</h3>

Given

P tot=750 mmHg

V₁=57 cm³

T₁=10 °C = 283 K

P₂ = 760 mmHg(STP)

T₂ = 273 K(STP)

Required

P dry gas at STP

Solution

Dalton's Law

P tot = P H₂O + P gas

P gas = 750 mmHg - 9.2 mmHg

P gas = 740.8 mmHg = P₁

Combined gas Law

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}\\\\V_2=\dfrac{P_1.V_1.T_2}{T_1.P_2}\\\\V_2=\dfrac{740.8\times 57\times 273}{283\times 760}=53.6~cm^3

7 0
3 years ago
Mnci, (aq) + 2H,O(1) CI,(A sample of 40.3 g Mno, is added to a solution containing 45.7 g HCI.What is the limiting reactant?ОMno
Luden [163]

In this question, we have the following reaction:

4 HCl + MnO2 -> MnCl2 + 2 H2O + Cl2

The reaction is already properly balanced, therefore we can take the molar ratios from it:

4 HCl = 1 MnO2

4 HCl = 1 Cl2

1 MnO2 = 1 Cl2

This shows us the molar ratio between the compounds, which means the number of moles needed for each compound in order for the reaction to occur, and this will also help us find the limiting and excess reactant

Now let's take the mass of each compound given in the question:

40.3 grams of MnO2, molar mass 86.94g/mol

45.7 grams of HCl, molar mass 36.46g/mol

Now let's check which one is the limiting, let's start with MnO2:

86.94g = 1 mol

40.3g = x moles

x = 0.463 moles of MnO2 in 40.3 grams

We know that whatever number of moles of MnO2 we have, we will require 4 times that of HCl, therefore

0.463 * 4 = 1.85 moles of HCl are required, but we don't know how much HCl we have, let's calculate it:

36.46g = 1 mol

45.7g = x moles

x = 1.25 moles, therefore we have less HCl than we actually need, this makes HCl the limiting reactant, and we have an excess of MnO2

Now for the theoretical yield of Cl2, we will use the number of moles of the limiting reactant, HCl 1.25 moles, in order to find the mass of Cl2, and again we need to look at the molar ratio, which is also 4:1, so the number of moles of Cl is HCl/4

Cl2 = HCl/4

Cl2 = 1.25/4

Cl2 = 0.312 moles

Now we take the molar mass of Cl2, 70.91g/mol, and find the final mass

70.91g = 1 mol

x grams = 0.312 moles

x = 22.12 grams of Cl2 is the theoretical yield

If we only have 85.1% of actual yield, the mass will be:

22.12g = 100%

x grams = 85.1%

x = 18.82 grams

Limiting reactant = HCl

Theoretical yield = 22.12 grams

Actual yield 85.1% = 18.82 grams

8 0
1 year ago
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