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3 years ago

11

an object sinks to the bottom of a container filled with water.what is the relationship between the weight of the object and the

buoyant force acting on it?

2 answers:

mars1129 [50]3 years ago

6 0

If the object sinks, then it must be heavier than the weight of the water
it displaces ... heavier than the buoyant force acting on it.

If the buoyant force were equal or greater than the object's weight, then
the object would rise to the surface in water.

olga55 [171]3 years ago

4 0

Answer: The buoyant force will be directly proportional to the weight of the object.

$F_B=\rho\times \frac{weight}{\rho_o}$

Explanation:

The buoyant force acting on the object immersed in liquid is given by:

$F_B=\rho gV$

$\rho$ = density if the liquid

V = Volume of the liquid displaced by the object

If an object sinks to the bottom of a container filled with water.This mans that volume displaced by the object is equal tho the volume of the object , $V=V_o$ .

$F_B=\rho gV$ ,

$F_B=\rho gV_o$

Density of the object:

= $\rho_o=\frac{\text{mass of the object}}{\text{Volume of the object}(V_o)}$

$F_B=\rho gV_o=\rho g\frac{Mass}{\rho_o}$

Weight of the object = $Mass\times g$

Since, weight is directly proportional to the mass of the object and mass of the object. So the buoyant force will be directly proportional to the weight of the object.

$F_B=\rho\times \frac{weight}{\rho_o}$

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A 0.74 mF capacitor is connected to a standard outlet (rms voltage 82 V, frequency 49 Hz ). Determine the magnitude of the curre

disa [49]

Answer:

I = 26.36 cosω t A

Explanation:

Given that

C=0.74 mF

Vrms= 82 V

Frequency ,f= 49 Hz

We know that ω = 2 π f

ω = 2 x π x 49

ω = 307.72 rad/s

As we know that voltage given as

V= Vo sinω t

$V_o=\sqrt2\ V_{rms}$

$V_o=\sqrt2\ \times 82$ \

Vo=115.96 V

V=115.96 sinω t

The current given as

$I=C\dfrac{dV}{dt}$

$I=0.74\times \dfrac{dV}{dt}\ mA$

$\dfrac{dV}{dt}=115.96\omega cos\omega t$

$I=0.74\times 115.96\times 307.22 cos\omega t\ mA$

I = 26362.67 cosω t mA

I = 26.36 cosω t A

This is the current at time ant time t.

7 0

3 years ago

A merry-go-round on a playground consists of a horizontal solid disk with a weight of 805 N and a radius of 1.58 m. A child appl

lozanna [386]

Answer:

The value is $KE = 259.6 \ J$

Explanation:

From the question we are told that

The weight of the horizontal solid disk is $W = 805 \ N$

The radius of the horizontal solid disk is $r = 1.58 \ m$

The force applied by the child is $F = 49.5 \ N$

The time considered is $t = 2.95 \ s$

Generally the mass of the horizontal solid disk is mathematically represented as

$m_h = \frac{W}{ g}$

=> $m_h = \frac{805}{ 9.8 }$

=> $m_h = 82.14 \ N$

Generally the moment of inertia of the horizontal solid disk is mathematically represented as

$I = \frac{1}{2} * m * r^ 2$

=> $I = \frac{1}{2} * 82.14 * 1.58^ 2$

=> $I = 102.5 \ kg \cdot m^2$

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

$T = I * \alpha = F * r$

=> $\alpha = \frac{ F * r }{ I }$

=> $\alpha = \frac{ 49.5 * 1.58 }{ 102.53 }$

=> $\alpha = 0.7628$

Gnerally from kinematic equation we have that

$w = w_o + \alpha t$

Here $w_o$ is the initial angular velocity velocity of the horizontal solid disk which is $w_o = 0\ rad/s$

So

$w = 0 + 0.7628 * 2.95$

=> $w = 2.2503 \ rad/s$

Generally the kinetic energy is mathematically represented as

$KE = \frac{1}{2} * I * w^2$

=> $KE = \frac{1}{2} * 102.53 * 2.2503 ^2$

=> $KE = 259.6 \ J$

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2 years ago

Two factors that regulate (control) glandular secretion.

antiseptic1488 [7]

Answer:

The factors include age and puberty

Explanation:

Glandular secretion release chemicals such as hormones in response to the body’s metabolic needs.

As an individual ages , the metabolic rate of the body also reduces . This is due to the stress and ageing of the cells of the body. This explains why glandular secretion is optimal with young people and Lower in older people. It also explains why the immune system of a young person is mostly stronger than older people.

Puberty is another factor which affects glandular secretion as during puberty there is usually a high amount of hormonal changes due to high levels of secretions of some hormones. These hormones could however inhibit the other glandular secretions.

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3 years ago

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natka813 [3]

Answer:

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As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.

So, the minimum length is 28 cm and the maximum length is 32 cm.

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