The correct answer is 1.07m.
The area surrounding an electric charge where its impact may be felt is known as the electric field. When another charge enters the field, the presence of an electric field may be felt. The electric field will either attract or repel the charge depending on its makeup. Any electric charge has a property known as the electric field. The charge and electrical force working in the field determine the strength or intensity of the electric field.
Here, is the charge per unit length, r is the distance from the wire, and
is the free space permittivity ε_0. Electric field due to the long straight wire is,
E= λ/2πε_0r
Rearrange the equation for r.
r=λ/2πε_0E
Substitute 2.41 N/C for E,
E=1.44×10^-10C/m
λ=8.85×10^-12C^2/Nm^2
r=(1.44×10^-10C/m)/(2(3.14)(8.85×10^-12C^2/Nm^2)(2.41N/C))
r=1.07m
At a distance of 1.07 m the magnitude of electric field is 2.41 N/C.
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Answer:
Explanation:
Let hotter star has surface area of A . The cooler star would have surface area 9 times that of hotter star ie 9A , because its radius is 3 times hot star. Let temperature of hot star be T ₁.
Total radiant energy is same for both the star
Using Stefan's formula of black body radiation,
For cold star E = 9A x σ T⁴
For hot star E = A x σ T₁⁴
A x σ T₁⁴ = 9A x σ T⁴
T₁⁴ = (√3)⁴T⁴
T₁ = √3T .
b )
Let the peak intensity wavelength be λ₁ and λ₂ for cold and hot star .
As per wein's law
for cold star , λ₁ T = b ( constant )
for hot star λ₂ √3T = b
dividing
λ₁ T / λ₂ √3T = 1
λ₂ / λ₁ = 1 / √3
Through an earth-based telescope you can see Jupiter more clearly than Mars because Jupiter is much larger than Mars and through the telescope you see the larger objects more clearly.
Answer:
negative, positive
Explanation:
A we know that the electrons have a negative charge.
So, when a body has some excess electrons, it means it has negative charge.
When a body has an deficiency of eletrons, it means it gains a positive charge.
An area with excess electrons has a net _<u>negative</u>__ charge; an area with a deficit of electrons has a net _<u>Positive</u>____ charge.