Answer:
1) The partial pressure of SO₂ gas in the larger container = 0.115 atm.
2) The partial pressure of N₂ gas in the larger container = 0.206 atm.
3) The total pressure in the vessel = 0.321 atm.
Explanation:
- To calculate the partial pressure of each gas, we can use the general law of ideal gas: PV = nRT.
where, P is the partial pressure of the gas in atm,
V is the volume of the vessel in L,
n is the no. of moles of the gas,
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas in K.
<u><em>1) What is the partial pressure of SO₂ gas in the larger container?</em></u>
<em>∵ P = nRT/V.</em>
n = mass/molar mass = (3.0 g)/(64.066 g/mol) = 0.047 mol.
R = 0.082 L.atm/mol.K.
T = 26 °C + 273.15 = 299.15 K.
V = 10.0 L. (The volume of the new container)
∴ P = nRT/V = (0.047 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.115 atm.
<u><em>2) What is the partial pressure of N₂ gas in the larger container?</em></u>
<em>∵ P = nRT/V.</em>
n = mass/molar mass = (2.35 g)/(28.0 g/mol) = 0.084 mol.
R = 0.082 L.atm/mol.K.
T = 26 °C + 273.15 = 299.15 K.
V = 10.0 L. (The volume of the new container)
∴ P = nRT/V = (0.084 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.206 atm.
<u><em>3) What is the total pressure in the vessel?</em></u>
- According to Dalton's law the total pressure exerted is equal to the sum of the partial pressures of the individual gases.
<em>∵ The total pressure in the vessel = the partial pressure of SO₂ + the partial pressure of N₂.</em>
∴ The total pressure in the vessel = 0.115 + 0.206 = 0.321 atm.
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