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Makovka662 [10]
3 years ago
8

Which of these is an advantage of shade-grown coffee beans?

Chemistry
1 answer:
victus00 [196]3 years ago
4 0

Answer: A

Explanation: I just took the quiz.

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Radiation is spontaneously emitted from hydrogen-3 nuclei, but radiation is not spontaneously emitted from hydrogen-l nuclei or
miv72 [106K]

Answer : Option 1) nuclei of H^{1} and nuclei of H^{2} only.


Explanation : Radiation is spontaneously emitted from nuclei of H^{3} because this isotope of hydrogen is highly radioactive as compared to other isotopes of hydrogen namely; nuclei of H^{1} and nuclei of H^{2}.


They have much stable nucleus as compared to nuclei of H^{3}.


The more it is unstable the more radiations will be emitted from its nucleus.

5 0
3 years ago
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Scientific knowledge results from the interaction of scientists who are investigating natural phenomena. Which of these BEST des
seraphim [82]

Answer:

5ywhxhghghghfhffgffgffg

Explanation:

6 0
3 years ago
What is energy in motion called
oee [108]
Is it kinetic energy
3 0
3 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
I dont understand this question can u guys help
diamong [38]

Answer: B

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Explanation:

6 0
2 years ago
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