All categories

3 years ago

Find the volume of a sphere that has a diameter of 40km

Mathematics

1 answer:

muminat3 years ago

6 0

Answer:

Step-by-step explanation:

volume of a sphere 4/3 pi r^3

vol=4/3 pi 20^3

= 4/3 x 3.1415x 8000

= 33510km^3

You might be interested in

What is the square root of -1?

Alchen [17]

Answer: √−1=i.

Step-by-step explanation: When we say that the square root of a negative number "doesn't exist", we mean that there is no real number solution. However, if we consider complex numbers, we then get a solution to √−1=i.

4 0

3 years ago

Read 2 more answers

About 5% of the population has a particular genetic mutation. 900 people are randomly selected.

Gelneren [198K]

I think u need to do 5%*900 which is 5 percent of 900. the answer might be 45 I'm not 100 percebt sure tho

8 0

4 years ago

Help me please!!!! i dont now the answer

Marat540 [252]

-1/10 is your answer .

7 0

3 years ago

7a = 49 in multiplication way?<br> SHOW ALL WORK

Olegator [25]

A WOULD BE 7 BECAUSE 7 TIMES 7 EQUALS 49

8 0

3 years ago

Read 2 more answers

A circular mirror is surrounded by a metal frame. The radius of the mirror is 2x. The side length of the metal frame is 12x. Wha

meriva

Answer:

$Area\ of\ th\e metal\ frame = 65.5x^{2}\ (unit)^{2}$

Step-by-step explanation:

Assuming that the metal frame is a square metal frame because the length of the side of the metal frame is given.

Given:

Radius of the mirror = 2x unit

Side length of the square metal frame = 12x unit

We need to find the area of the metal frame.

Solution:

First we find the area of the circular mirror, using area formula of the circle.

$A_{c} = \pi r^{2}$

Where, r = Radius of the object.

Substitute r = 2x in above equation.

$A_{c} = \pi (5x)^{2}$

$A_{c} = \pi (25x^{2})$

$A_{c} = 25\pi x^{2}\ (unit)^{2}$

Now, we find the area the square, using area formula of the square.

$A_{S} = (Side\ length)^{2}$

$A_{S} = (12x)^{2}$

$A_{S} = 144x^{2}\ (unit)^2}$

So, the area of the square metal frame is given as

$A_{f}=A_{s}-A_{c}$

$A_{f}=144x^{2}-25\pi x^{2}$

$A_{f}=(144-25\pi) x^{2}$

$A_{f}=(144-25\times 3.14) x^{2}$

$A_{f}=(144-78.5) x^{2}$

$A_{f}=65.5 x^{2}\ (unit)^{2}$

Therefore, the area of the metal frame is $65.5x^{2}\ (unit)^{2}$ .

5 0

3 years ago