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2 years ago

If you increase the mass but leave the volume the same what happens to the density of the object

1 answer:

3 0

Density is a property of an object or substance that can be described through the correlation of the mass of an object over its volume.

Mathematically, density = mass / volume.
In description, the relationship of density and mass is positively correlated and with volume, inversely.
Since density and mass is positively correlated then if you increase the mass, the density of the object will also increase leaving density and volume the same.

Example:
Mass = 10 g changes to 20
Volume = 5 cm3
Density =?

1. D = m / v
2. D = 10 g / 5 cm3
3. D = 2 g / cm3
4. D = 20 g / 5 cm3
5. D = 4g/cm3

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An iron railroad rail is 800 ft long when the temperature is 31°C. What is its length (in ft) when the temperature is −17°C?

natta225 [31]

Answer:

799.54 ft

Explanation:

Linear thermal expansion is:

ΔL = α L₀ ΔT

where ΔL is the change in length,

α is the linear thermal expansion coefficient,

L₀ is the original length,

and ΔT is the change in temperature.

Given:

α = 1.2×10⁻⁵ / °C

L₀ = 800 ft

ΔT = -17°C − 31°C = -48°C

Find: ΔL

ΔL = (1.2×10⁻⁵ / °C) (800 ft) (-48°C)

ΔL = -0.4608

Rounded to two significant figures, the change in length is -0.46 ft.

Therefore, the final length is approximately 800 ft − 0.46 ft = 799.54 ft.

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2 years ago

The frequency of a microwave is 1.2 x 10^9 hertz. what is the wavelength of the given problem.

Olenka [21]

Answer:

0.25 m

Explanation:

Electromagnetic waves consist of oscillations of the electric and the magnetic field, oscillating in a plane perpendicular to the direction of motion the wave.

All electromagnetic waves travel in a vacuum always at the same speed, the speed of light, whose value is:

$c=3.0\cdot 10^8 m/s$

Microwave is an example of electromagnetic waves.

The relationship between wavelength and frequency for an electromagnetic wave is:

$\lambda=\frac{c}{f}$

where

$\lambda$ is the wavelength

$c=3.0\cdot 10^8 m/s$ is the speed of light

f is the frequency

For the microwave in this problem,

$f=1.2\cdot 10^9 Hz$

So its wavelength is

$\lambda=\frac{3.0\cdot 10^8}{1.2\cdot 10^9}=0.25 m$

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pochemuha

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