In which case would electrical potential energy be built up and stored in the electric field? a) A positive charge is moved towa
1 answer:
You might be interested in
Answer:
the lowest possible frequency of the emitted tone is 404.79 Hz
Explanation:
Given the data in the question;
S₁ ← 5.50 m → L
↑
2.20 m
↓
S₂
We know that, the condition for destructive interference is;
Δr = ( 2m + ) × λ
where m = 0, 1, 2, 3 .......
Path difference between the two sound waves from the two speakers is;
Δr = √( 5.50² + 2.20² ) - 5.50
Δr = 5.92368 - 5.50
Δr = 0.42368 m
v = f × λ
f = ( 2m + )v / Δr
m = 0, 1, 2, 3, ....
Now, for the lowest possible frequency, let m be 0
so
f = ( 0 + )v / Δr
f = (v) / Δr
we know that speed of sound in air v = 343 m/s
so we substitute
f = (343) / 0.42368
f = 171.5 / 0.42368
f = 404.79 Hz
Therefore, the lowest possible frequency of the emitted tone is 404.79 Hz
As we know from the Newton's II law we can say
here if force is unbalanced then it is for sure that net force on the system is non zero
so here the object must have some acceleration here
so here we can say that object must have change in velocity due to unbalanced force present on it
now the correct option in this case must satisfy the change in velocity condition.
SO correct answers will be
<em>Decelerate. </em>
<em>Stop moving. </em>
<em>Start moving. </em>
<em> Accelerate. </em>