Answer:
Explanation:
initial velocity, u = 8 m/s
vertical height, h = 1 m
θ = 40°
Let the horizontal distance is d and the time taken is t.
Use second equation of motion in vertical direction
h = ut + 1/2 at²
1 = 8 Sin 40 x t + 0.5 x 9.8 t²
1 = 5.14 t - 4.9t²
4.9t² - 5.14 t + 1 = 0
so, t = 0.26 s (smaller value)
So, the horizontal distance is
d = u cos 40 x t
d = 8 cos 40 x 0.26
d = 1.6 m
A thunder bolt and lightning strike wouldn't do anyone any favours and might well account for the mess and the broken windows ...
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<h2>Answer:</h2>
<u>Angular velocity of bicycle tire is 15.78 radians per second.</u>
<h3>Explanation:</h3>
Angular velocity is the change in angular speed of an object with respect to time take for change or it is the rate of change of circular motion.
In the given question the circular displacement is 25 rounds around a central point.
The angular displacement is measured in degrees and 1 round is equal to 360 degrees.
25 Rounds = 25 × 360 = 9000 degrees.
Angular velocity = angular displacement /time = 9000/10 = 900 degrees per second.
In SI,angular velocity is represented in radians per second.
So, 1 radian = 57.29 degrees
Angular velocity = 15.78 radians per second
A 1 complete revolution corresponds to an angular displacement of 2π rad, or 360º. (So there are 180º for every π rad.) Also, there are 60 seconds to 1 minute. So, the angular velocity in rad/s is
(2000 rev/min) * (2π rad/rev) * (1/60 min/s) = 200π/3 rad/s
or approximately 209.44 rad/s.
B First convert the angular velocity to degrees per second (º/s):
(200π/3 rad/s) * (180/π º/rad) = 12,000 º/s
We want to find the time <em>t</em> it would take for the propeller to turn 36º:
36º = (12,000 º/s) <em>t</em>
==> <em>t</em> = 36º / (12,000 º/s) = 3/1000 s
or approximately 0.003 s.
