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marysya [2.9K]
3 years ago
15

Giving lots of points

Physics
2 answers:
bekas [8.4K]3 years ago
5 0

Answer:

wind turbine

Explanation:

antiseptic1488 [7]3 years ago
4 0

Answer:

g wind turbine

Explanation:

look up the song dancing in the sky

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A car travels 35 km west and 90 km north in two hours what is its average velocity?
blagie [28]
Average velocity =  Total Displacement / Total time taken

Total displacement is the distance from starting to end point.

35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle. 

So displacement = \sqrt{35^2+90^2}

= 96.56 km

So, Total displacement = 96.56 km

So, Average Velocity = 96.56 / 2  = 48.28 km/hr
8 0
3 years ago
explain why a circulatory system is important in meeting the needs of all cells throughout an animals body
Effectus [21]
Helps ur blood circulate, to ur head and ect helpin u leave
7 0
3 years ago
Calculate how much work you need to move a 280 N shed to a platform 5 m above.
castortr0y [4]
Work is done when a motion resulted from the force being done by an object. The amount of work done is calculated by multiplying the force applied and the distance traveled. It is calculated as follows:

Work = Force x distance = 280 N x 5 m  =  1400 J.
6 0
3 years ago
SOMEONE HELP ME PLEASE!!!!!
enyata [817]

Answer:

I think it would be the 3rd or 4th one.

8 0
3 years ago
How will the electrostatic force between two electric charges change if the first charge is doubled and the second charge is onl
Vinvika [58]

Answer:

B) \frac{2}{3}

Explanation:

The electric force between charges can be determined by;

F = \frac{kq_{1} q_{2} }{r^{2} }

Where: F is the force, k is the Coulomb's constant, q_{1} is the value of the first charge, q_{2} is the value of the second charge, r is the distance between the centers of the charges.

Let the original charge be represented by q, so that;

q_{1} = 2q

q_{2} = \frac{q}{3}

So that,

F = q_{1}q_{2} x \frac{k}{r^{2} }

  = 2q x \frac{q}{3} x \frac{k}{r^{2} }

  = \frac{2q^{2} }{3} x \frac{k}{r^{2} }

  = \frac{2}{3} x \frac{kq}{r^{2} }

F = \frac{2}{3} x \frac{kq}{r^{2} }

The electric force between the given charges would change by \frac{2}{3}.

4 0
3 years ago
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