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denis23 [38]
3 years ago
5

suppose you needed to build a raft to cross a fast-moving river. Describe the physical and chemical properties of the raft that

would be important to ensure your safety.
Physics
1 answer:
erastovalidia [21]3 years ago
4 0
1.Density of the material building the raft must be lower than the water. 
<span>2. Material must not react with water. </span>
<span>3.Material must have high strength. </span>
<span>4.Raft must be wide in-order to avoid drawing in the river.</span>
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Q: A: The long distance water movement, from roots up to leaves, of the water transport in large plants depends on one unique pr
ICE Princess25 [194]
Answer: B

Cohesion makes water stick together, which is vital in transporting nutrients from tree roots to other parts of the plant.
4 0
3 years ago
Read 2 more answers
Calculate the centripetal force exerted on the earth by the sun. Assume that the period of revolution for the earth is 365.25 da
Doss [256]

Answer:

F = 3.55 x 10²² N

Explanation:

average distance of sun from earth = 1.5 × 10⁸ km

mass of earth = 6 x 10²⁴ kg

time = 365.25 days

distance = 2 π r

distance = 2 π x 1.5 x 10¹¹ m

              = 3 π x 10¹¹ m

v = \dfrac{d}{t}

v = \dfrac{3 \pi \times 10^{11}}{365.25 \times 24 \times 60 \times 60}

   v = 2.98 x 10⁴ m/s

we know centripetal force

F = \dfrac{mv^2}{r}

F = \dfrac{6 \times 10^{24}\times (2.98\times 10^4)^2}{1.5\times 10^{11}}

F = 3.55 x 10²² N

8 0
3 years ago
The net external force on a golf cart is 395.2 n north. if the cart has a total mass of 259.1 kg, what is the cart's acceleratio
yKpoI14uk [10]
Applying the Newton Second Law of motion that is F=ma
We have F=395.2N (North) and m=259.1Kg

Putting these values in the equation

395.2 = 259.1 x a than
for a = 395.2/259.1
a = 1.525 m/sec 2
8 0
3 years ago
A rectangular wooden block measures 10.0 cm × 4.00 cm × 2.00 cm. When the block is placed in water, it floats horizontally, with
Alex Ar [27]

Answer:

825 kgm⁻³

Explanation:

ρ = density of wood = ?

ρ' = density of water = 1000 kgm⁻³

V = volume of wood = 10 x 4 x 2 = 80 cm³ = 80 x 10⁻⁶ m³

V' = Volume of water displaced = 10 x 4 x 1.65 = 66 cm³ = 66 x 10⁻⁶ m³

Using equilibrium of force in vertical direction

Force of buoyancy = Weight of the wood

ρ' V' g = ρ V g

ρ' V' = ρ V  

(1000) (66 x 10⁻⁶) = ρ (80 x 10⁻⁶)

ρ = 825 kgm⁻³

5 0
3 years ago
Beginning at time t = 0, a student exerts a horizontal force on a box of mass 30 kg, causing it to move at 1.2 m/s toward an ele
Alexandra [31]
Since the initial and the final velocity are just equal, it is implied that the acceleration is zero. This means that the net force acting on the body is also zero. The horizontal force should be equal to the force of friction. The force of friction is equal to the product of the coefficient and the normal force. 
                               

 Ff = (coefficient of friction) x Fn


The normal force is equal to the object's weight if the surface is horizontal.


                               Ff = (0.20) x (30 kg) x (9.8 m/s²)  = 58.8 N
<span>

<span>Thus, the horizontal force exerted must be 58.8 N. 

--------------------------------------


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span></span>
6 0
3 years ago
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