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lapo4ka [179]
3 years ago
11

Can somebody help me on one question?? It’s really easy it’s just that I wanna make sure if it’s right so please help :) will ma

rk brainliest:)

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
8 0

Answer:

x ≤6

Step-by-step explanation:

-3x ≥-18

Divide each side by -3. Remember that flips the inequality.

-3x/-3 ≤-18/-3

x ≤6

s344n2d4d5 [400]3 years ago
6 0

Answer:

x  < = (less than) 6

Step-by-step explanation:

-3x > = -18

x  < = (less than) 6

You're Correct

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What is 5 1/2 of 60%
EleoNora [17]
You mean 60%of 5 1/2? that makes more sense...


i would do it like this:

\frac{60}{100}* 5\frac{1}{2}

(60% is the same as \frac{60}{100}

5\frac{1}{2}=\frac{11}{2}

(so that there is no confusion, i've put it into an improper fraction

now we can multiply:
\frac{60}{100}* \frac{11}{2}=

\frac{6}{10}* \frac{11}{2}=

\frac{3}{5}* \frac{1}{2}=



\frac{3*11}{10}=

\frac{33}{10}=

which is 3.3.

so 60% of 5 and a half is 3.3.


6 0
3 years ago
Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antid
vredina [299]

Answer:

6t + \frac{t^2}{2}+2/5t^{5/2} + C

Step-by-step explanation:

Given the expression;

g(t) = 6 + t + t²/√t

This can be rewritten as;

g(t) = 6 + t +t²/t^1/2

g(t) = 6 + t +t^{2-1/2}

g(t) = 6 + t +t^3/2

Integrate the result

\int\limits {(6 + t+t^{3/2}}) \, dt\\

Using the formula x^{n+1}/n+1

\int\limits {(6  + t+t^{3/2}}) \, dt\\ = 6t + \frac{t^2}{2}+\frac{t^{3/2+1}}{3/2 + 1} \\ = 6t + \frac{t^2}{2}+\frac{t^{5/2}}{5/2} \\= 6t + \frac{t^2}{2}+2/5t^{5/2} + C

5 0
3 years ago
How to solve it the answer
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She gave away 8 apples because 13 minus 5 is 8
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3 years ago
Find the slope of a line that is parallel and the slope of a line that is perpendicular to each line whose equation is given. Pl
aleksley [76]
The equations above are all in the format y = mx + c, where m = the gradient, or slope.

So, in the first question, y = 4x + 2, the gradient would be 4, because 4 is m in this equation (the number before the x).

The gradient of a line perpendicular to this line is equal to the negative reciprocal of the gradient of the line. A better way to explain it is if m = the gradient of the line and <u />m' = the gradient of the perpendicular line then:
m' = - \frac{1}{m}

So in the first question, the gradient of the perpendicular line is - \frac{1}{4}.
4 0
4 years ago
Square root! Please explain!
Anon25 [30]

Answer:

a number which produces a specified quantity when multiplied by itself.

Step-by-step explanation:

4 0
3 years ago
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