All categories

2 years ago

Why is it important that the mouth and stomach are near the start of the digestive system? thx

Physics

2 answers:

xxTIMURxx [149]2 years ago

8 0

Because the mouth breaks down the food and the stomach uses acid to break food down even more

zaharov [31]2 years ago

8 0

Answer: To complete the process of digestion after the food is ingested by mouth.

Explanation:

The food that we eat is ingested by mouth and here the mechanical degradation of food takes place. This breaks down the food into smaller pieces.

Mouth also contains the enzyme that is responsible for the digestion of starch.

Then the food from the mouth reaches the stomach where various types of digestive juices and enzymes are secreted to digested the food.

Hence, mouth and stomach must be near in the digestive system.

You might be interested in

A 92-kg fullback moving south with a speed of 5.8 m/s is tackled by a 110-kg lineman running west with a speed of 3.6 m/s. Assum

MariettaO [177]

Answer:

The speed and direction of the two players immediately after the tackle are 3.3 m/s and 53.4° South of West

Explanation:

given information:

mass of fullback, $m_{x}$ = 92 kg

speed of full back, $v_{x}$ = 5.8 to south

mass of lineman, $m_{y}$ =110 kg

speed of lineman, $v_{y}$ = 3.6

according to conservation energy,

assume that the collision is perfectly inelastic, thus

initial momentum = final momentum

$P_{ix}$ = $P_{x}$ '

m₁v₁ = (m₁+m₂) $v_{x}$ '

$v_{x}$ ' = m₁v₁/(m₁+m₂)

= (92) (5.8)/(92+110)

= 2.64 m/s

$P_{iy}$ = $P_{y}$ '

m₂v₂ = (m₁+m₂) $v_{y}$ '

$v_{y}$ ' = m₁v₁/(m₁+m₂)

= (110) (3.6)/(92+110)

= 1.96 m/s

thus,

$v$ ' = √ $v_{x}$ '²+ $v_{y}$ '²

= 3.3 m/s

then, the direction of the two players is

θ = 90 - tan⁻¹( $v_{y}$ '/ $v_{x}$ ')

= 90 - tan⁻¹(1.96/2.64)

= 53.4° South of West

7 0

2 years ago

A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5

harkovskaia [24]

Answer:

The kinetic energy is: 50[J]

Explanation:

The ball is having a potential energy of 100 [J], therefore

PE = [J]

The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

$E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\$

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

$P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\$

This energy is equal to the kinetic energy, therefore

Ke= 50 [J]

8 0

3 years ago

Ag,Au and Cu are called coinage metals why plzzzz hurry its urgent plzzz

Ronch [10]

Answer:

This is because these metals are used for minting (making) coins.

8 0

3 years ago

A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.

salantis [7]

Answer:

130m

Explanation:

You just have to multiply velocity by the time traveled:

100m/s * 1.3s = 130m!

5 0

3 years ago

Read 2 more answers

A 20 g sparrow flying toward a bird feeder mistakes the pane of glass in a window for an opening and slams into it with a force

Rama09 [41]

I found this using the app Socratic. When I took physics in high school it helped me so much.

5 0

3 years ago