Let
be the height of the building and thus the initial height of the ball. The ball's altitude at time
is given by
![y=y_0+\left(15\dfrac{\rm m}{\rm s}\right)\sin35^\circ\,t-\dfrac g2t^2](https://tex.z-dn.net/?f=y%3Dy_0%2B%5Cleft%2815%5Cdfrac%7B%5Crm%20m%7D%7B%5Crm%20s%7D%5Cright%29%5Csin35%5E%5Ccirc%5C%2Ct-%5Cdfrac%20g2t%5E2)
where
is the acceleration due to gravity.
The ball reaches the ground when
after
. Solve for
:
![0=y_0+\left(15\dfrac{\rm m}{\rm s}\right)\sin35^\circ(2.9\,\mathrm s)-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(2.9\,\mathrm s)^2](https://tex.z-dn.net/?f=0%3Dy_0%2B%5Cleft%2815%5Cdfrac%7B%5Crm%20m%7D%7B%5Crm%20s%7D%5Cright%29%5Csin35%5E%5Ccirc%282.9%5C%2C%5Cmathrm%20s%29-%5Cdfrac12%5Cleft%289.80%5Cdfrac%7B%5Crm%20m%7D%7B%5Cmathrm%20s%5E2%7D%5Cright%29%282.9%5C%2C%5Cmathrm%20s%29%5E2)
![\implies y_0\approx16.258\,\mathrm m](https://tex.z-dn.net/?f=%5Cimplies%20y_0%5Capprox16.258%5C%2C%5Cmathrm%20m)
so the building is about 16 m tall (keeping track of significant digits).
Answer:
Explanation:
v= u + at
v is final velocity , u is initial velocity . a is acceleration and t is time
Initial velocity u = 0 . Putting the given values in the equation
v = 0 + g sin 18 x 3.5
= 10.6 m /s
Answer:
B. stearothermophilus and S. ruber
Explanation:
B. stearothermophilus and S. ruber
In solar evaporation ponds the temperature is higher and the salt concentration is also higher because of the water evaporated so sunder such extreme conditions this hybrid bacteria is capable of surviving. B. stearothermophilus is thermophilus bacteria which grows at high temperature and S. ruber is halophilic bacteria which grows in saline environment. So, these two bacteria best suited for the above hybrid condition.
Answer:
When an electromagnetic wave passes from space to matter, some part of the energy is absorbed by the matter and it increases its energy. The wave may reflect and some part may pass through the matter depending on the amount of energy they have. The amplitude of the wave decreases if some parts of it are reflected.
Answer:
A= 148.92 m/s²
Explanation:
Given that
U(x,y) = (6.00 )x² - (3.75 )y ³
m= 0.04 kg
Now force in the x-direction
Fx= - dU/dx
U(x,y) = (6.00 )x² - (3.75 )y ³
dU/dx= 12 x
When x=0.4 m
dU/dx= 12 x 0.4 = 4.8
So we can say that
Fx= - 4.8 N
From Newtons law
F= m a
- 4.8 = 0.04 x a
a = -120 m/s²
Acceleration in x direction ,a = -120 m/s²
In y -direction
F= - dU/dy
U(x,y) = (6.00 )x² - (3.75 )y ³
dU/dy = 0 - 3.75 x 3 y²
When y = 0.56 m
dU/dy = - 3.75 x 3 x 0.56 x 0.56
dU/dy = - 3.52
So we can say that force in y -direction
F= 3.52 N
F= m a'
3.52 = 0.04 x a'
a'=88.2 m/s²
acceleration in y direction is 88.2 m/s²
The resultant acceleration
![A=\sqrt{a^2+a'^2}](https://tex.z-dn.net/?f=A%3D%5Csqrt%7Ba%5E2%2Ba%27%5E2%7D)
![A=\sqrt{120^2+88.2^2}](https://tex.z-dn.net/?f=A%3D%5Csqrt%7B120%5E2%2B88.2%5E2%7D)
A= 148.92 m/s²