Answer:
3. Large butterfly in flight, flying through the air?
Explanation:
Momentum is simply defined as the quantity of motion a body possess. It is mathematically given as;
Momentum = mass x velocity
The larger the mass, the larger the momentum and also the velocity
Since the large butterfly is in flight, it has the largest velocity.
A sleeping bear and resting caterpillar have no momentum because their velocity is 0
This term absolute location refers to using another location as a reference point, rather than using latitude and longitude.
Answer:
The appropriate response will be "Length must be increased by 0.012%".
Explanation:
The given values is:
ΔT = 5 s/day
Now,
⇒ 
On multiplying both sides by "100", we get
⇒ 
⇒
(%)
∵ 
On substituting the values, we get
⇒
% =
%
On applying cross multiplication, we get
⇒
% =
%
⇒ = 
⇒ = 
⇒ =
%
The three ways a person can manipulate light
would be the following:,
filter, and the time the photograph is taken
<span>1.
</span>Angle
- <span>The </span>camera angle<span> <span>marks
the specific location at which the movie </span></span>camera<span> <span>or
video </span></span>camera<span> is
placed to take a shot.</span>
<span>2.
</span>Filter - Camera<span> <span>lens </span></span>filters<span> <span>still have many uses in digital photography,
and should be an important part of any photographer's </span></span>camera<span> bag.</span>
<span>3.
</span>Time
the photograph is taken - The golden hour, sometimes called the "magic
hour", is roughly the first hour of light after sunrise, and the last hour
of light before sunset, although the exact duration varies between seasons.
During these times the sun is low in the sky, producing a soft, diffused light
which is much more flattering than the harsh midday sun that so many of us are
used to shooting in.
I am hoping that these answers
have satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
Answer:
The box will be moving at 0.45m/s. The solution to this problem requires the knowledge and application of newtons second law of motion and the knowledge of linear motion. The vertical component of the force Fp acts vertically upwards against the directio of motion. This causes a constant upward force of 23sin45° to act on the box. Fhe frictional force of 13N also acts vertically upwards and so two forces act upwards against rhe force of gravity resulting un a net force of 0.7N acting kn the box. This corresponds to an acceleration of 0.225m/s². So in w.0s after i start to push v = 0.45m/s.
Explanation: