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nalin [4]
3 years ago
6

A base has a molarity of 1.5M w.R.T the hydroxyl ion concentration. If 7.35 cm3 of this base is taken and diluted to 147 cm3, th

en what is the concentration of the hydroxyl ion.
Chemistry
1 answer:
daser333 [38]3 years ago
4 0

Answer:

0.077M is the concentration of the hydroxyl ion

Explanation:

Dilution factor is the ratio between the aliquot that is taken of a solution and the total volume of the diluted solution.

For the problem, dilution factor is:

7.53cm³ / 147cm³ =<em> 0.05122</em>

To obtain molarity of a diluted solution you must multiply dilution factor and initial molarity of the solution, thus:

1.5 M × 0.05122 = <em>0.077M is the concentration of the hydroxyl ion</em>

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Phosphorus can be prepared from calcium phosphate by the following reaction:

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

Phosphorite is a mineral that contains Ca_3(PO_4)_2 plus other non-phosphorus-containing compounds. What is the maximum amount of P_4 that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75% Ca_3(PO_4)_2 by mass? Assume an excess of the other reactants.

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Explanation:

Given mass of phosphorite Ca_3(PO_4)_2  = 2.3 kg

As given percentage of phosphorite Ca_3(PO_4)_2 is = \frac{75}{100}\times 2.3kg=1.725kg=1725g

moles=\frac{\text {given mass}}{\text {Molar mass}}

{\text {moles of}Ca_3(PO_4)_2=\frac{1725g}{310g/mol}=5.56moles

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

According to stoichiometry:

2 moles of phosphorite gives = 1 mole of P_4

Thus 5.56 moles of phosphorite give= \frac{1}{2}\times 5.56=2.78moles of P_4

Mass of P_4=moles\times {\text {Molar mass}}=2.78mol\times 124g/mol=345g=0.345kg

Thus the maximum amount of P_4 that can be produced is 0.345 kg

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