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Valentin [98]
3 years ago
13

The nonvolatile, nonelectrolyte testosterone, C19H28O2 (288.40 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressur

e generated when 12.9 grams of testosterone are dissolved in 286 ml of a benzene solution at 298 K.
Chemistry
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

3.824 atm

Explanation:

From the ideal gas equation

P = mRT/MW × V

m is mass of testosterone = 12.9 g

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of benzene solution = 298 K

MW is molecular weight of testosterone = 288.40 g/mol

V is volume of benzene solution = 286 ml = 286 cm^3

P = 12.9×82.057×298/288.4×286 = 3.824 atm

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Answer: With the cold front, warm air is rapidly forced upward (like the shavings) in advance of the actual front (the “cutter”), creating towering cumulus clouds, some hard showers and quite possibly a few gusty thunderstorms followed by a push of cooler and drier air in its wake.

Explanation:

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3 years ago
How many moles of hydrogen gas are needed to produce 20 grams of hydrochloric acid (HCl)?
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Answer:

0.27 mole

Explanation:

Data given:

mass of hydrochloric acid (HCl) = 20 g

moles of hydrogen (H₂O) = ?

Solution:

First we look to the reaction in which hydrogen react with Chlorine and make hydrochloric acid (HCl)

Reaction:

              H₂ + Cl₂ -----------> 2HCl

Now look at the reaction for mole ratio

              H₂ + Cl₂ -----------> 2HCl

              1 mole                    2 mole

So it is 1:2 mole ratio of hydrogen to hydrochloric acid (HCl)

As we Know

molar mass of H₂ = 2(1) = 2 g/mol

molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Now convert moles to gram

                     H₂         +       Cl₂    ----------->     2HCl

            1 mole (2 g/mol)                             2 mole (36.5 g/mol)

                     2 g                                                 73 g

So,

we come to know that 2 g of hydrogen gives 73 g of hydrochloric acid (HCl) then how many grams of hydrogen will be required to produce 20 grams of hydrochloric acid (HCl).

Apply unity formula

                            2 g of H₂ ≅ 73 g of HCl

                            X g of H₂ ≅ 20 g of HCl

Do cross multiplication

                            X of H₂ = 2 g x 20 g / 73 g

                            X of H₂ = 0.55 g

Now convert grams of H₂ into moles

                    No. of moles = mass in grams/molar mass

Put values in above formula

                   No. of moles = 0.55 g / 2 (g/mol)

                   No. of moles = 0.27 mol

0.27 mole of hydrogen needed to produce 20 gram of hydrochloric acid (HCl).

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Explanation:

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