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Valentin [98]
2 years ago
13

The nonvolatile, nonelectrolyte testosterone, C19H28O2 (288.40 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressur

e generated when 12.9 grams of testosterone are dissolved in 286 ml of a benzene solution at 298 K.
Chemistry
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:

3.824 atm

Explanation:

From the ideal gas equation

P = mRT/MW × V

m is mass of testosterone = 12.9 g

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of benzene solution = 298 K

MW is molecular weight of testosterone = 288.40 g/mol

V is volume of benzene solution = 286 ml = 286 cm^3

P = 12.9×82.057×298/288.4×286 = 3.824 atm

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3 years ago
Universal indicator solution
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Shred red cabbage ~ (3/4 of a very small head)

Put the cabbage pieces in a small container ~ ( you can use a Pyrex-4-cup measure, a bowl or even a plastic zipper bag)

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Now look for substances that may be acids or bases. 
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You can also use solids around for baking are good too. (such as baking soda, salt, sugar, cream of tartar...)

Get containers for mixing (such as tea cups, because they are small, shallow and white inside)

Pour the indicator into the tea cups and add an acid or base.

Lemon juice, rice wine vinegar, and apple cider vinegar, turn the cabbage-water indicator into a pink.

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An egg white (which won't get into the solution immediately until after a lot of stirring) turns the cabbage-water indicator blue.

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Answer:

B

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