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Valentin [98]
2 years ago
13

The nonvolatile, nonelectrolyte testosterone, C19H28O2 (288.40 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressur

e generated when 12.9 grams of testosterone are dissolved in 286 ml of a benzene solution at 298 K.
Chemistry
1 answer:
dolphi86 [110]2 years ago
6 0

Answer:

3.824 atm

Explanation:

From the ideal gas equation

P = mRT/MW × V

m is mass of testosterone = 12.9 g

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of benzene solution = 298 K

MW is molecular weight of testosterone = 288.40 g/mol

V is volume of benzene solution = 286 ml = 286 cm^3

P = 12.9×82.057×298/288.4×286 = 3.824 atm

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What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?
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The  empirical formula  for a compound   is KClO3

     Explanation 
 
find  the  moles of each  element
moles  = % composition/molar  mass

molar  mass of  of  potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles  of potassium  =  31.9 / 39 = 0.818  moles
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moles of   oxygen  =  39.2/  16 =  2.45  moles


find the  mole ratio  by  dividing   with  the smallest  mole = 0.814  moles

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