Answer:
3 water molecules
Explanation:
The molar ratio between CuSO₄ and H₂O needs to be calculated.
The mass of water that was removed by heating is calculated, then converted to moles. The molecular weight of water is 18.02g/mol.
(8.97 g - 6.57 g) = 2.22 g H₂O
(2.22 g)/(18.02g/mol) = 0.1232 mol H₂O
The moles of anhydrous copper sulfate are calculated. The molecular weight is 159.609 g/mol
(6.57 g)/(159.609 g/mol) = 0.04116 mol CuSO₄
Now the molar ratio between CuSO₄ and H₂O can be calculated:
0.1232 mol H₂O ÷ 0.04116 mol CuSO₄ = 3 H₂O / CuSO₄
Answer:
The answer to your question is Aluminum
Explanation:
Number of clues
1.- If this element has 3 rings in its Bohr model, we are looking for and element located in the third period of the periodic table.
For example Sodium, Magnesium, Aluminum, Silicate, Phosphorus, Sulfur, Chlorine and, Argon.
2.- It makes three bonds to become stable, then we are looking for and element located in the third group like
Boron, Aluminum, Gallium, Indium, etc
Conclusion
The element that has both characteristics is Aluminum
