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Black_prince [1.1K]
3 years ago
8

Determine the potential difference between two charged parallel plates that are 0.50 cm apart and have an electric field strengt

h of 9.0 V/cm.
Physics
2 answers:
jeka57 [31]3 years ago
5 0
If the field strength between the plates is 9 volts per cm, then over a path of 1/2cm parallel to the field, the potential changes by (1/2) x (9 volts) = 4.5 volts.
zheka24 [161]3 years ago
3 0
E =  \frac{V}{r} \\ V =  \frac{E}{r}  \\ V =  \frac{9.0V/cm}{0.5cm} \\ V = 18V
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Explanation:

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