For this problem, we use the equations derived for rectilinear motion at constant acceleration. The equations are:
a = (v - v₀)/t
x = v₀t + 0.5at²
where
a is acceleration
v and v₀ are the final and initial velocities, respectively
x is the distance
t is the time
First, let's determine the a to be used in the second equation:
a = (7.5 m/s - 0 m/s)/1.7 s = 4.411 m/s²
x = (0)(1.7s) + 0.5(4.411 m/s²)(1.7 s)²
x = 6.375 m
Answer:
4.36 rad/s
Explanation:
Radius of platform r = 2.97 m
rotational inertia I = 358 kg·m^2
Initial angular speed w = 1.96 rad/s
Mass of student m = 69.5 kg
Rotational inertia of student at the rim = mr^2 = 69.5 x 2.97^2 = 613.05 kg.m^2
Therefore initial rotational momentum of system = w( Ip + Is)
= 1.96 x (358 + 613.05)
= 1903.258 kg.rad.m^2/s
When she walks to a radius of 1.06 m
I = mr^2 = 69.5 x 1.06^2 = 78.09 kg·m^2
Rotational momentuem of system = w(358 + 78.09) = 436.09w
Due to conservation of momentum, we equate both momenta
436.09w = 1903.258
w = 4.36 rad/s
Answer:
With Boyle's law we have that for a constant temperature and gas quantity the pressure of a gas multiplied by its volume is also constant: This means that under the same temperature, two gases with equal quantity of molecules and equal volume must also have the same pressure, as well as that two gases with equal quantity and pressure must have the same volume.
Explanation:
Atoms are made up of three particles: protons, neutrons and electrons. Protons and neutrons are heavier than electrons and reside in the center of the atom, which is called the nucleus.Jun 5, 2013-livescience.com
Answer:
Explanation:
λ = hc/¢
Where
h = the Plank constant 6.63 x 10-34 Is
C = 3.0×10^8
¢= 1.96eV
= (6.63×10^-34Js)×(3×10^8)÷( 1.96eV) × 1eV/1.6×10^-19J
= (1.989×10^-25)÷( 1.96eV)×1eV/1.6×10^-19J
= 6.342×10^-7m
B) maximum kinetic energy
= K=hf−ϕ ........1
ϕ = hc
Where
h = constant 6.63 x 10^-34Js
ϕ= 1.96eV
Recall
λ =425×10^-9m
f = frequency in Hz
f = c / λ
C = 3.0×10^8
f = 3.0×10^8 / 425×10^-9m
f = 0.000705Hz
From equation 1
K = (6.63 x 10^-34Js×0.000705Hz )- 6.63 x 10^-34Js×3.0×10^8
= 4.68×10^-37 - 1.989×10^-25
= - 1.98×10^-25J