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Vocabulary word for the total amount of charge in a closed system remains constant

Usimov [2.4K]

Answer:

i think this is it i dont know tho A conservation law stating that the total electric charge of a closed system remains constant over time, regardless of other possible changes within the system. "Conservation of charge." YourDictionary. LoveToKnow

7 0

3 years ago

Which of the following is not true about elements.

alexgriva [62]

Answer:

C

Explanation:

elements are classified as covalent, ionic, metallic

8 0

3 years ago

On August 10, 1972, a large meteorite skipped across the atmosphere above the western United States and western Canada, much lik

Anon25 [30]

a) $4.62\cdot 10^{14} J$

b) 0.110 megatons

c) 8.46 bombs

Explanation:

a)

The energy lost by the meteorite is equal to the difference between its final kinetic energy and its initial kinetic energy:

$\Delta K=K_f-K_i$

Which can be rewritten as:

$\Delta K=\frac{1}{2}mv^2-\frac{1}{2}mu^2$

where:

$m=3.2\cdot 10^6 kg$ is the mass of the meteorite

$v=0$ is the final speed of the meteorite

$u=17 km/s = 17,000 m/s$ is the initial speed of the meteorite

Substituting the values into the equation, we found the loss in energy of the meteorite:

$\Delta K=0-\frac{1}{2}(3.2\cdot 10^6)(17000)^2=-4.62\cdot 10^{14} J$

So, the energy lost by the meteorite is $4.62\cdot 10^{14} J$

b)

The energy equivalent to 1 megaton of TNT is

$E_{TNT}=4.2\cdot 10^{15} J$

Here the energy lost by the meteorite is

$E=4.62\cdot 10^{14} J$

Therefore, in order to write the energy lost by the meteorite as a multiple of the energy of 1 megaton of TNT, we have to divide the energy lost by the meteorite by the energy equivalent to 1 TNT; we find:

$\frac{E}{E_{TNT}}=\frac{4.62\cdot 10^{14}}{4.2\cdot 10^{15}}=0.110$

So, the energy lost by the meteorite corresponds to 0.110 megatons.

c)

The energy of one atomic bomb explosion in Hiroshima is equal to

$E'=13 kt$ (13 kilotons)

which corresponds to

$E'=0.013 Mt$ (0.013 megatons)

Here the energy of the meteorite is equal to

$E=0.110 Mt$ (0.110 megatons)

Therefore, we can find how many Hiroshima bombs are equivalent to teh meteorite impact by using the following rules of three:

$\frac{1 bomb}{0.013 Mt}=\frac{x bombs}{0.110 Mt}\\x=\frac{1\cdot 0.110}{0.013}=8.46$

So, 8.46 bombs.

5 0

3 years ago

A book is moved once around the perimeter of a tabletop with dimensions 1.2 m x 1.8 m.

Goryan [66]

Answer:

a) 0m

b) 6m

Explanation:

First, we need to remember:

Displacement: Difference between final and initial position.

Distance traveled: Total distance traveled.

a) If the final position is the same as the initial position, then:

final position = initial position

And we know that:

displacement = final position - initial position = 0

Then the displacement of the book is zero.

b)

We can assume that the book traveled along the perimeter of the table.

The table is a rectangle of width 1.2m and length 1.8m

Remember that for a rectangle of width W and length L, the perimeter is:

P = 2*L + 2*W

Then the perimeter of the table is:

P = 2*1.2m + 2*1.8m = 6m

This means that the distance traveled by the book is 6 meters.

3 0

2 years ago

Why is a frequency distribution useful? It allows researchers to see the "shape" of the data. It tells researchers how often the

11Alexandr11 [23.1K]

Answer: Frequency distribution helps to understand data. some complex data needs to be converted into intervals to see its frequency of occurrence. it helps to find the mean median and mode of the data. It helps in the analysis of data and its practical implementation.

Explanation:

7 0

3 years ago

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