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Irina-Kira [14]
3 years ago
8

A QL = -26 μC charge is placed on the x-axis at x = - 0.2 m. A QR = 26 μC charge is placed at x = +0.2 m. (for all answers below

assume that the unit vector x^ points toward positive x, and y^ points towards positive y.).
What is the x-component of the electric field at x = 0 m and y = 0.2 m?
What is the y-component of the electric field at x = 0 m and y = 0.2 m?
What is the x-component of the electric field at x = 0 m and y = -0.2 m?
What is the y-component of the electric field at x = 0 m and y = -0.2 m?
Physics
1 answer:
Kaylis [27]3 years ago
4 0
<span>You are given a QL = -26 μC charge that is placed on the x-axis at x = - 0.2 m and a QR = 26 μC charge that is placed at x = +0.2 m. The answers are:

The x-component of the electric field at x = 0 m and y = 0.2 m is 3.
The y-component of the electric field at x = 0 m and y = 0.2 m is 2.

</span>
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Answer:

3, 5, 1, 4, 2

Explanation:

When the body needs to move, certain muscles need to be stimulated in order to perform a certain movement. There is a process that is followed that starts with the brain sending a signal, and ends with the movement being performed by the body.

3. This is the first step, because a pathway needs to be established before any electric impulses can be sent. Hence, the upper motor neurons in the premotor cortex <u>need to choose a pathway</u> (known as a motor program).

5. This is the second step, because once a pathway has been established, a <u>signal needs to be sent</u> down that pathway. Hence, the basal nuclei enable the thalamus to stimulate the upper motor neurons to send an electrical impulse down the pathway.

1. This is the third step, because once the upper motor neurons have been stimulated, they send an electrical impulse to stimulate the lower motor neurons.

4. This is the forth step, because once the electrical impulse reaches the lower motor neurons, they pass the impulse to a certain group of skeletal muscles, causing them to contract.

2. This is the final step, because once the skeletal muscles have contracted, the <u>body has completed its movement</u>. However, once the body has moved, sensory information is relayed to the cerebellum to <u>ensure that the correct movement is made</u>, and if it needs to be adjusted, then the whole process will start again in order to correct the movement.

4 0
3 years ago
When a 0.622 kg basketball hits the floor, its velocity changes from 4.23 m/s down to 3.85 m/s up. If the ball was in contact wi
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when the ball hits the floor and bounces back the momentum of the ball changes.

the rate of change of momentum is the force exerted by the floor on it.

the equation for the force exerted is

f = rate of change of momentum

f = \frac{mv - mu}{t}

v is the final velocity which is - 3.85 m/s

u is initial velocity - 4.23 m/s

m = 0.622 kg

time is the impact time of the ball in contact with the floor - 0.0266 s

substituting the values

f = \frac{0.622 kg (3.85 m/s - (-)4.23 m/s)}{0.0266}

since the ball is going down, we take that as negative and ball going upwards as positive.

f = 189 N

the force exerted from the floor is 189 N

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3 years ago
2. A cinder block is sitting on a platform 20 m high. It weighs 16kg. The block has
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Answer:

3136 Joules

Explanation:

Applying,

P.E = mgh.............. Equation 1

Where P.E = potential energy, m = mass of the cinder block, h = height of the platform, g = acceleration due to gravity.

From the question,

Given: m = 16 kg, h = 20 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P.E = 16(20)(9.8)

P.E = 3136 Joules

Hence the potential energy of the cinder block is 3136 Joules

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Answer: mass x height x gravitational field strength (g)

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