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olga_2 [115]
3 years ago
6

What do group 2 elements have in common

Physics
1 answer:
Leokris [45]3 years ago
3 0
Although many characteristics are common<span> throughout the </span>group<span>, the heavier metals such as Ca, Sr, Ba, and Ra are almost as reactive as the </span>Group<span> 1 Alkali Metals. All the </span>elements<span> in </span>Group 2 have two<span> electrons in their valence shells, giving them an oxidation state of +</span><span>2.</span>
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Two floors in a building are separated by 4.1 m. People move between the two floors on a set of stairs. (a) Determine the change
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Answer:

a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

Explanation:

Let consider the bottom of the first floor in a building as the zero reference (z = 0\,m). The change in potential energy experimented by a particle (\Delta U_{g}), measured in joules, is:

\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o}) (1)

Where:

m - Mass, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

z_{o}, z_{f} - Initial and final height with respect to zero reference, measured in meters.

Please notice that m\cdot g is the weight of the particle, measured in newtons.

a) If we know that m = 3\,kg, g = 9.807\,\frac{m}{s^{2}}, z_{o} = 0\,m and z_{f} = 4.1\,m, then the change in potential energy is:

\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)

\Delta U_{g} = 120.626\,J

The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) If we know that m\cdot g = 650\,N, z_{o} = 4.1\,m and z_{f} = 0\,m, then the change in potential energy is:

\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)

\Delta U_{g} = -2665\,J

The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

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