Given : The Intelligence Quotient (IQ) test scores for adults are normally distributed with a population mean of $\mu=100$ and a population standard deviation of $\sigma=15$ .

Sample size = 50

Using formula $z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$ , the z-value corresponding to x=98 will be:-

$z=\dfrac{98-100}{\dfrac{15}{\sqrt{50}}}\approx-0.94$

Z-value corresponding to x=103 will be:-

$z=\dfrac{103-100}{\dfrac{15}{\sqrt{50}}}\approx1.41$

Using the standard normal distribution table for z-scores, we have

P-value = $P(98$

Hence, the probability we could select a sample of 50 adults and find that the mean of this sample is between 98 and 103 = 0.7471

8 0

4 years ago

I don’t get this...!!!

notka56 [123]

Ray CB, because it will include point A in the ray
Rays go on forever in one direction, so Ray CB and Ray CA are the same because they're going in the same direction

3 0

4 years ago

What is the value of f(x)=25^2-10x+1

spin [16.1K]

When y=0, x=62.6 use Desmos.

3 0

3 years ago