Ask question

Ask question

All categories

3 years ago

12

What is the perimeter of the actual garden?

1 answer:

Lilit [14]3 years ago

4 0

Answer: 576 inches or 48 feet

Step-by-step explanation:

set up a proportion where $\frac{drawing AB}{actual AB} =\frac{drawing perimeter}{actual perimeter}$

so you get drawingAB = 24 in

actualAB = 18 feet = 18 * 12 in = 216 in

drawing perimeter = 64 in

so plug these in to get $\frac{24}{216} =\frac{64}{actual perimeter}$

rearrange to get $actual perimeter = \frac{216 * 64}{24}$

and solve to get 576 inches or 576/12 = 48 feet

You might be interested in

(4.3*10^4)^2 in scientific notation

xeze [42]

1.849x10^9 or 1.849e9

3 0

3 years ago

Find the vertices and foci of the hyperbola with equation quantity x plus 1 squared divided by 225 minus the quantity of y plus

miss Akunina [59]

Answer:

The vertices are (-16,-5) and (14,-5)

The foci are (-26,-5) and (24,-5)

6 0

3 years ago

First let’s go on a trip! you come into some money and decide to go to canada where the exchange rate is 1.04 canadian dollars t

Ksenya-84 [330]

13092.50 Canadian dollars equals to $10000 US dollars.

6 0

3 years ago

Evaluate the indefinite integral. (Use C for the constant of integration.) sin(10x) 1 cos2(10x) dx

Schach [20]

Answer:

The result of the integral is $-\frac{\cos^3{10x}}{30} + C$

Step-by-step explanation:

We are given the following integral:

$\int \sin{(10x)}\cos^{2}{(10x)} dx$

I am going to solve by substitution, using $u = \cos{10x}$ , so $du = -10\sin{10x}dx, dx = -\frac{du}{10\sin{10x}}$ . So, we have

$-\frac{1}{10} \int u^2 du$

Which has the following result:

$-\frac{u^3}{30} + C$

Going back to x, the result of the integral is

$-\frac{\cos^3{10x}}{30} + C$

5 0

3 years ago

Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than

liraira [26]

Given:

Atul has $\dfrac{2}{3}$ lb of candy.

Jose has $\dfrac{3}{5}$ lb of candy.

Maria has $\dfrac{1}{2}$ lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has $\dfrac{1}{2}$ lb less than Jose, therefore

Maria has = $\dfrac{3}{5}-\dfrac{1}{2}$ lb

Maria has = $\dfrac{6-5}{10}$ lb

Maria has = $\dfrac{1}{10}$ lb

Difference between the candies Atul and Maria have.

Difference = $\dfrac{2}{3}-\dfrac{1}{10}$ lb

Difference = $\dfrac{20-3}{30}$ lb

Difference = $\dfrac{17}{30}$ lb

Therefore, Atul have $\dfrac{17}{30}$ lb of candy more than Maria.

6 0

3 years ago