Using Coulomb's Law <span>
F = {k(Q1)(Q2)}/r²
Where F =force in Newtons, k = Coulomb constant, Q1 = - Q2=
charge of the objects in Coulumbs, and r is the distance between the objects.
Solving for r:
r = sqrt[{k(Q1)(Q2)}/F]
where k = 8.897 x 10^9 N•m²/C², Q1 = 2.5 C, Q2 = -2.5 C, and
F = -700 N
Note: Negative magnitude of Force indicates attraction.
<span>r = 8,912.77 m</span></span>
Answer:
Explanation:
Ruler. A steel ruler aids the measurement and layout of straight lines. The ruler, also called "straightedge" or "straight-edged ruler," is a long, thin strip of wood, metal or plastic marked with increments of measurement.
Measuring Tape. The modern measuring tape's roughly palm-sized casing contains a coiled strip of metal marked with increments of measurement. The metal strip, called "tape," attaches to a spring which automatically retracts the tape into the casing following use.
Walking Tape Measure. The walking tape measure, also called "surveyor's measure," records the distance traveled by a wheel. An operator pushes the measure's wheel, similar to a bicycle wheel, by a handle as an attached ticker box displays feet or meters in the same format as a car's odometer.
Laser Measure. The laser measure offers point and shoot distance measurement. In its most basic form, a laser measure is a hand-held electronic device with a digital display.
U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
Answer:
Tension, T = 2558.59 N
Explanation:
It is given that,
Mass of the box, m = 400 kg
The box is lifted vertically upward with constant velocity by means of two cables pulling at 40 degrees on either side of the vertical direction. Since, the cables are symmetrical. So, tension will be same on each cable.
T = 2558.59 N
So, the tension in each cable is 2558.59 N. Hence, this is the required solution.
Answer:
(a)
907.11 rad/s²
(b)
4082 rad
Explanation:
(a)
t = time taken = 3.00 s
w₀ = initial angular velocity of the drill = 0 rad/s
w = final angular velocity of the drill = 26000 rev/min = 26000 
= 2721.33 rad/s
α = angular acceleration of the drill
t = time interval = 3.00 s
using the equation
w = w₀ + α t
2721.33 = 0 + α (3)
α = 907.11 rad/s²
(b)
θ = angle
using the equation
θ = w₀ t + (0.5) α t²
θ = (0) (3.00) + (0.5) (907.11) (3.00)²
θ = 4082 rad
