The kinetic energy before equals K after
Acceleration is the
rate of change of velocity, a body moving with uniform velocity does not
possess acceleration at all i.e. acceleration is zero
I have two (2) brilliant ideas:
1). Inside the metal that the body of the car is made of, and also between the two sheets of glass that the windows are made of, install a thin layer of material that absorbs RF (radio-wave) energy . . . like the material in the glass window of your microwave oven. Then, no radio waves from the cellular base station can get INTO the car, and no radio waves from your phone can get OUT of the car. The phone can't make a connection to the cellular network, you can't make or receive calls, and you can't connect to Instagram or Brainly, so you might as well just turn it off and save your battery until next time you're outside your car.
2). Somewhere inside the car, like under the dash or in the glove box, install a teeny tiny radio receiver that can recognize the signals coming OUT of your phone. Connect it to the car's electrical system so that when it hears signals from phones inside the car, it it shuts down the car's motor so you can't start or drive. The car only works when phones inside the car are either turned off or in Airplane Mode.
My ideas are so brilliant that I really should patent them, or copyright them, or whatever you do so that other people have to pay you to use your idea. But if you want to use them, that's OK. Just go ahead. I won't mind.
Answer:
Hello your question is incomplete attached below is the complete question
Answer : x ( acceleration of mass 4m ) = ![\frac{g}{7}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7B7%7D)
The top pulley rotates because it has to keep the center of mass of the system at equilibrium
Explanation:
Given data:
mass suspended = 4 meters
mass suspended at other end = 3 meters
first we have to express the kinetic and potential energy equations
The general kinetic energy of the system can be written as
T = ![\frac{4m}{2} x^2 + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2](https://tex.z-dn.net/?f=%5Cfrac%7B4m%7D%7B2%7D%20x%5E2%20%20%2B%20%5Cfrac%7B3m%7D%7B2%7D%20%28-x%2By%29%5E2%20%2B%20%5Cfrac%7Bm%7D%7B2%7D%20%28-x-y%29%5E2)
T =
also the general potential energy can be expressed as
U = ![-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant](https://tex.z-dn.net/?f=-4mgx-3mg%28-x%2By%29-mg%28-x-y%29%2Bconstant%3D-2mgy%20%2Bconstant)
The Lagrangian of the problem can now be setup as
![L =4mx^2 +2my^2 -2mxy +2mgy + constant](https://tex.z-dn.net/?f=L%20%3D4mx%5E2%20%2B2my%5E2%20-2mxy%20%2B2mgy%20%2B%20constant)
next we will take the Euler-Lagrange equation for the generalized equations :
Euler-Lagrange equation = ![4x-y =0\\-2y+x +g = 0](https://tex.z-dn.net/?f=4x-y%20%3D0%5C%5C-2y%2Bx%20%2Bg%20%3D%200)
solving the equations simultaneously
x ( acceleration of mass 4m ) = ![\frac{g}{7}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7B7%7D)
The top pulley rotates because it has to keep the center of mass of the system at equilibrium
By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.
<h3>What are the limits?</h3>
First, we need to find the limits.
We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.
So if 58 in is the 100%, the 26% and 43% of that are:
- 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
- 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.
But we know that the CG is found to be 45.5% MAC, then it measures:
(45.5%/100%)*58in = 0.455*58in = 26.39 in
We need to compare it with the largest limit, so we get:
26.39 in - 24.94 in = 1.45 in
This means that the CG is 1.45 inches out of limits.
If you want to learn more about percentages, you can read:
brainly.com/question/14345924